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我正在尝试使用以下代码在 Angularjs 中编写待办事项应用程序。

function write_controller($scope){
  $scope.todos = [{text:'hey all',done:false}, 
                 {text:'hello',done:false}];
  $scope.addtodo = function(){
  $scope.todos.push({text:$scope.todopush,done:false});
    $scope.todopush = '';
  }
  $scope.delete = function(){
    var oldtodos = $scope.todos;
    $scope.todos = [];
    angular.forEach(oldtodos, function(x){
      if (!x.done){
        $scope.todos.push(x);}
    });
  };
}
<html ng-app>
    <head>
     <script src =  
     "https://ajax.googleapis.com/ajax/libs/angularjs/1.0.7/angular.min.js">   
      </script>
      </head>
      <body>
      <div class = "basic_class" ng-controller = "write_controller">
      <ul>
        <li ng-repeat = "todo in todos"><input type = "checkbox" ng-model  
         ="todo.done">{{todo.text}}</input></li>
      </ul>
      <input type = "text"
        placeholder = "please add data here"
        ng-model="todopush">
      </input>
      <input type = "button" ng-click ="addtodo()" value ="Click me!!"></input>
      <input type = "button" ng-click = "delete()" ng-model="remove" value =  
       "remove!"></input>
      </div>
</body>
</html>

在下面的代码中，我有以下问题。删除操作如何工作？

我的理解：1）它将现有数组推入一个新数组2）它清除现有数组3）迭代新数组3）检查完成的功能？？？（当它说 !x.done 时，它​​是对还是错？？？）任何帮助将不胜感激。

4

1 回答 1

1

走过这些步骤

$scope.delete = function() {
    // store existing todos array in variable
    var oldtodos = $scope.todos;
    // create new empty array for todos
    $scope.todos = [];
    // loop over previously stored todos
    angular.forEach(oldtodos, function(x) {//x is element of the array - a single todo object
      // if x.done is not truthy
      if (!x.done){
       // push this item into `$scope.todos`
       $scope.todos.push(x);
    });
}

基本上它只会将其推done:false入新版本，$scope.todos从而有效地删除done:true

于 2016-10-09T03:53:26.497 回答