5

在 Programming Game Screeps 中,我使用以下方法生成小兵:

if(transporters.length < 0 && harvesters.length > 2) {
var newName = Game.spawns['SpawnZone'].createCreep([WORK,CARRY,MOVE], undefined, {role: 'transporter'});
console.log('Spawning new Transporter: ' + newName);
}

“未定义”标签用于生成具有随机名称的cree。现在我想知道,既然我有不同类型的小兵,我是否可以在它前面添加一个角色标签?例如,[Transporter] RandomName。

那可能吗?

4

5 回答 5

10

我发现仅仅用他们的工作和当前的游戏时间来命名就可以很好地满足需求。

例如:"Builder" + Game.time.toString()= Builder1234

一个 spawn 一次只能制造一个小兵,因此名称应该始终是唯一的。

唯一的问题是,如果 2+ 生成器尝试同时制作一个机器人(相同的滴答声),那么没有首先开始生成的人将失败ERR_NAME_EXISTS,但您可以在下一个周期中获取它们。

在此处输入图像描述

于 2016-11-21T19:13:10.323 回答
5

您可以实现一个函数,该函数将以您想要的格式生成名称并替换undefined为生成的名称。来自 Screeps文档

createCreep(body, [name], [memory])

开始蠕变生成过程。可以从房间中的所有生成和扩展中提取所需的能量。

[...]

名称(可选)字符串

一个新creep的名字。它应该是唯一的creep 名称,即Game.creeps 对象不应包含另一个具有相同名称(哈希键)的cree。如果未定义,将生成一个随机名称。

Screeps 论坛实际上已经为您提供了解决方案。成绩单如下:

var names1 = ["Jackson", "Aiden", "Liam", "Lucas", "Noah", "Mason", "Jayden", "Ethan", "Jacob", "Jack", "Caden", "Logan", "Benjamin", "Michael", "Caleb", "Ryan", "Alexander", "Elijah", "James", "William", "Oliver", "Connor", "Matthew", "Daniel", "Luke", "Brayden", "Jayce", "Henry", "Carter", "Dylan", "Gabriel", "Joshua", "Nicholas", "Isaac", "Owen", "Nathan", "Grayson", "Eli", "Landon", "Andrew", "Max", "Samuel", "Gavin", "Wyatt", "Christian", "Hunter", "Cameron", "Evan", "Charlie", "David", "Sebastian", "Joseph", "Dominic", "Anthony", "Colton", "John", "Tyler", "Zachary", "Thomas", "Julian", "Levi", "Adam", "Isaiah", "Alex", "Aaron", "Parker", "Cooper", "Miles", "Chase", "Muhammad", "Christopher", "Blake", "Austin", "Jordan", "Leo", "Jonathan", "Adrian", "Colin", "Hudson", "Ian", "Xavier", "Camden", "Tristan", "Carson", "Jason", "Nolan", "Riley", "Lincoln", "Brody", "Bentley", "Nathaniel", "Josiah", "Declan", "Jake", "Asher", "Jeremiah", "Cole", "Mateo", "Micah", "Elliot"]
var names2 = ["Sophia", "Emma", "Olivia", "Isabella", "Mia", "Ava", "Lily", "Zoe", "Emily", "Chloe", "Layla", "Madison", "Madelyn", "Abigail", "Aubrey", "Charlotte", "Amelia", "Ella", "Kaylee", "Avery", "Aaliyah", "Hailey", "Hannah", "Addison", "Riley", "Harper", "Aria", "Arianna", "Mackenzie", "Lila", "Evelyn", "Adalyn", "Grace", "Brooklyn", "Ellie", "Anna", "Kaitlyn", "Isabelle", "Sophie", "Scarlett", "Natalie", "Leah", "Sarah", "Nora", "Mila", "Elizabeth", "Lillian", "Kylie", "Audrey", "Lucy", "Maya", "Annabelle", "Makayla", "Gabriella", "Elena", "Victoria", "Claire", "Savannah", "Peyton", "Maria", "Alaina", "Kennedy", "Stella", "Liliana", "Allison", "Samantha", "Keira", "Alyssa", "Reagan", "Molly", "Alexandra", "Violet", "Charlie", "Julia", "Sadie", "Ruby", "Eva", "Alice", "Eliana", "Taylor", "Callie", "Penelope", "Camilla", "Bailey", "Kaelyn", "Alexis", "Kayla", "Katherine", "Sydney", "Lauren", "Jasmine", "London", "Bella", "Adeline", "Caroline", "Vivian", "Juliana", "Gianna", "Skyler", "Jordyn"]

Creep.getRandomName = function(prefix){
    var name, isNameTaken, tries = 0;
    do {
        var nameArray = Math.random() > .5 ? names1 : names2;
        name = nameArray[Math.floor(Math.random() * nameArray.length)];

        if (tries > 3){
            name += nameArray[Math.floor(Math.random() * nameArray.length)];
        }

        tries++;
        isNameTaken = Game.creeps[name] !== undefined;
    } while (isNameTaken);

    return prefix+" "+name;
}
于 2016-10-01T19:00:26.310 回答
3

与@Matthew-Regul 类似,我只是给了他们一个随机序列号,附在他们的职责上:

'UPGRADER_' + (Math.floor(Math.random() * 65534) + 1)

虽然他消除了重复名字的极微小的可能性

于 2016-11-23T18:13:42.663 回答
0

我发现 screeps 中缺少默认的命名方案,因为名称并没有太多说明crees 的作用。为此,我编写了一个名为 util.nameBuilder 的小型实用程序类。

它用于Memory.nameIndex = {};跟踪前缀被分配给creep的次数。因为如果蠕变的生成失败,我不想随机增加计数,所以我有 agetName(role)和 a commitName(role)getName()返回一个名称以供使用,commitName()并将计数增加 1。如果计数超过某个阈值(例如 1000),您可能希望“折叠”计数,以防止像harvester243874 这样的名称。commitName(role)如果createCreep()返回“名称已在使用”错误,我的 spawn 方法将实际调用。

此代码的结果是这样的名称:harvester1、builder23、upgrader5

var nameBuilder = {
    getName: function(role) {
        if (Memory.nameIndex === undefined)
            Memory.nameIndex = {};

        if (Memory.nameIndex[role] === undefined) 
            Memory.nameIndex[role] = 0;

        return role + (Memory.nameIndex[role] + 1);
    },

    commitName: function(role) {
        var newIndex = Memory.nameIndex[role] + 1;
        Memory.nameIndex[role] = newIndex;
    }
};

module.exports = nameBuilder;
于 2016-10-19T14:54:21.200 回答
0
"Upgrader_" + spawn.name + "_" + Game.time

创建一个保证的唯一名称。

于 2021-08-12T20:32:15.147 回答