1

我正在使用 Oracle 10g。我有以下关系结构,我认为我需要将其展平,因此在客户端,网格视图显示正确的列数。

可以将下面的表 A 配置为使用启用字段启用或禁用其中的任何一个记录。

TableB 通过字段 fk 存储与 TableA 相关的计算值。对于 docid 1,有为“nm1”和“nmn4”计算的值,但没有为“nm2”计算的值。

我的问题是,对于 TableA 的特定配置,无论 TableB 中的 docid 是否具有计算值,我都需要返回一个记录集,该记录集具有 TableA 中已启用记录的完整补充。我希望动态创建的输出如下所示。

有任何想法吗?

TableA
id     nm     enabled
1     'nm1'   1
2     'nm2'   1
3     'nm3'   0
4     'nm4'   1


TableB
id     fk(A.id)     docid     value
1      1            1         .8
2      4            1         .6
3      1            2         .3
4      2            2         .4
5      4            2         .7
6      2            3         .6
7      4            3         .8

Output as records
1     'nm1'     .8       'nm2'     null     'nm4'     .6
2     'nm1'     .3       'nm2'     .4       'nm4'     .7
3     'nm1'     null     'nm2'     .6       'nm4'     .8
4

2 回答 2

1

对我来说,这看起来像是数据透视查询的一个亚种。您可以通过将表 B 与表 A 连接起来进行过滤,然后限制启用(类似于select B.* from B, A where B.A_id = A.id and A.enabled = 1)。然后你可以转动它。

于 2010-10-20T17:03:03.987 回答
0

我确信有更好的方法可以做到这一点,但这就是我想出的。此外,您发布的问题似乎有点模糊,所以我不完全确定我是否正确回答了这个问题。

首先,您需要获取所有可能结果的稀疏表,然后再次加入以获取值。

这将输出作为单列数据。如果不使用动态 SQL 或其他东西创建查询,实际上不可能为每个查询拥有自定义数量的列。

sys_connect_by_path 用于将多行数据连接成一行。

with table_a as (
  select 1 as id, 'nm1' as nm, 1 as enabled from dual union all
  select 2 as id, 'nm2' as nm, 1 as enabled from dual union all
  select 3 as id, 'nm3' as nm, 0 as enabled from dual union all
  select 4 as id, 'nm4' as nm, 1 as enabled from dual
),
table_b as (
  select 1 as id, 1 as a_id, 1 as docid, 0.8 as value from dual union all
  select 2 as id, 4 as a_id, 1 as docid, 0.6 as value from dual union all
  select 3 as id, 1 as a_id, 2 as docid, 0.3 as value from dual union all
  select 4 as id, 2 as a_id, 2 as docid, 0.4 as value from dual union all
  select 5 as id, 4 as a_id, 2 as docid, 0.7 as value from dual union all
  select 6 as id, 2 as a_id, 3 as docid, 0.6 as value from dual union all
  select 7 as id, 4 as a_id, 3 as docid, 0.8 as value from dual 
),
cartesian_prod as (
  select b.docid, a.id, a.nm
  from 
    table_a a
    cross join (select distinct docid from table_b) b
  where a.enabled = 1
)
select 
  docid, 
  ltrim(max(sys_connect_by_path(nm || ' ' || value, ', ')), ', ') as value
from (
  select 
    c.docid, 
    c.nm, 
    nvl(to_char(b.value), 'null') as value, 
    row_number() over (partition by c.docid order by c.id) as rown
  from 
    cartesian_prod c 
    left outer join table_b b on (b.docid = c.docid and c.id = b.a_id)
)
start with rown = 1
connect by docid = prior docid and rown = prior rown + 1
group by docid
于 2010-10-20T15:25:34.673 回答