0

我有以下代码演示问题:

@Component
public class App {
    @Autowired S1 s1;
    @Autowired S2 s2;
    int jobs = 0;
    @Scheduled(cron = "0 * * * * ?")
    void foo() {
        System.out.println("schedule cron job: " + jobs++);
        Observable<String> observable = Observable.just("bar");
        ConnectableObservable<String> publishedObservable = observable.publish();
        publishedObservable.subscribe(s1);
        publishedObservable.subscribe(s2);
        publishedObservable.connect();
    }
}

订阅者1:

@Component
public class S1 extends Subscriber<String> {
    private AtomicInteger counter = new AtomicInteger(0);

    @Override
    public void onCompleted() {
    }

    @Override
    public void onError(Throwable e) {
    }

    @Override
    public void onNext(String s) {
        System.out.println("S1:::: Times called: " + counter.getAndIncrement() + ", input: " + s);

    }
}

订阅者2:

@Component
public class S2 extends Subscriber<String> {
    private AtomicInteger counter = new AtomicInteger(0);

    @Override
    public void onCompleted() {
    }

    @Override
    public void onError(Throwable e) {
    }

    @Override
    public void onNext(String s) {
        System.out.println("S2:::: Times called: " + counter.getAndIncrement() + ", input: " + s);
    }
}

输出将是:

schedule cron job: 0
S1:::: Times called: 0, input: bar
S2:::: Times called: 0, input: bar
schedule cron job: 1
schedule cron job: 2
schedule cron job: 3
schedule cron job: 4
......

为什么每次调用 foo 方法时不调用 S1 和 S2 ?如何做到这一点?

这是因为 rx 一些订阅逻辑还是因为这些 bean 是单例的?

4

1 回答 1

2

为什么每次调用 foo 方法时不调用 S1 和 S2 ?

RxJavaSubscriber是有状态的,一旦它们消费了一个序列,它们就不再可用并报告自己为取消订阅。再次订阅他们没有任何效果。每次需要订阅源时,您都必须重新创建它们。

于 2016-09-28T11:39:39.217 回答