1

假设我在 Spring XD 中有一个自定义模块（我正在使用 Spring XD + Spring Integration + hibernate）。该模块基本上从数据库中获取一些东西（假设我使用休眠实体存储它，所以我使用一个名为“DataFromDB”的对象）。DataFromDB 是一个列表，然后我从列表中获取每个元素，我想使用以下方式发送它：

String payload = convertDataFromDBToJson(record);
return MessageBuilder.createMessage(payload, message.getHeaders());
  • 问题是每次我必须发送一条消息时，我都必须返回一条消息。
  • 所以我想遍历 DataFromDB 列表并将每个元素作为消息发送。

有没有办法发送多条消息？

编辑：

我只是根据试图复制场景的评论创建了一个小例子。这就是我所拥有的：

我的变压器类：

public class TransformerClass {
public Collection<Message<?>> transformerMethod(Message<?> message) {
    List<Message<?>> messages = new ArrayList<Message<?>>();
    messages.add(new GenericMessage<>("foo"));
    messages.add(new GenericMessage<>("bar"));
    return messages;
}

我的xml配置：

    <?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:int="http://www.springframework.org/schema/integration"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:tx="http://www.springframework.org/schema/tx"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/integration http://www.springframework.org/schema/integration/spring-integration.xsd
        http://www.springframework.org/schema/tx  http://www.springframework.org/schema/tx/spring-tx.xsd">

    <tx:annotation-driven />
    <int:channel id="input" />

    <bean id="transFormerClass" class="myModule.TransformerClass">
    </bean>

    <int:transformer input-channel="input" output-channel="output" ref="transFormerClass" method="transformerMethod"/>

    <int:channel id="output"/>

</beans>

我的测试课：

    @ModuleName(value = "someModule", type = ModuleType.processor)
public class TransformerClassTest extends xDTest {
    private String streamName = "myStream";
    private String chainTest = "someModule";

    @SuppressWarnings("unchecked")
    @Test
    public void testPartnerNotification() throws IOException {

        this.chain = SingleNodeProcessingChainSupport.chain(application, streamName, chainTest);
        //Just to send something to the module as a input.
        Message<String> input = MessageBuilder.createMessage("hello world", buildHeaders());
        this.chain.send(input);
        //Receiving a Single message
        Message<String> result = (Message<String>) chain.receive(5000);
        System.out.println("Result: " + result);
    }

    private MessageHeaders buildHeaders() {
        Map<String, Object> hashMap = new HashMap<String,Object>();
        hashMap.put("test", "testing");
        MessageHeaders headers = new MessageHeaders(hashMap);
        return headers;
    }    
}

输出是：

结果：GenericMessage [payload=[GenericMessage [payload=foo, headers={timestamp=1475072951345, id=7b6c79a2-db85-563e-c238-262a31141456}], GenericMessage [payload=bar, headers={timestamp=1475072951345, id=31c8ef0e -3513-b95e-3a25-4fd3550f2fea}]]，标头={timestamp=1475072951347，id=f90d94c4-e323-70ed-62ee-4b8bce64814d，测试=测试}]

我正在使用 Spring Integration 4.2.2.RELEASE。

4

1 回答 1

5

如果您返回 a Collection<Message<?>>，它们将作为单独的消息发送。

编辑

@EnableIntegration
@Configuration
public class So39708474Application {

    @Bean
    public DirectChannel input() {
        return new DirectChannel();
    }

    @Bean
    public DirectChannel output() {
        return new DirectChannel();
    }

    @Bean
    public Foo foo() {
        return new Foo();
    }

    public static class Foo {

        @ServiceActivator(inputChannel = "input", outputChannel = "output")
        public Collection<Message<?>> handle(Message<?> in) {
            List<Message<?>> messages = new ArrayList<Message<?>>();
            messages.add(new GenericMessage<>("foo"));
            messages.add(new GenericMessage<>("bar"));
            return messages;
        }

    }

}

和

@RunWith(SpringRunner.class)
@ContextConfiguration(classes = So39708474Application.class)
public class So39708474ApplicationTests {

    @Autowired
    private MessageChannel input;

    @Autowired
    private SubscribableChannel output;

    @Test
    public void contextLoads() {
        AtomicInteger count = new AtomicInteger();
        this.output.subscribe(m -> {
            count.incrementAndGet();
            System.out.println(m);
        });
        this.input.send(new GenericMessage<>("test"));
        assertEquals(2, count.get());
    }

}
于 2016-09-26T18:28:03.117 回答