66

如何创建一个同时具有可选参数和参数的方法?

static void Main(string[] args)
{

    TestOptional("A",C: "D", "E");//this will not build
    TestOptional("A",C: "D"); //this does work , but i can only set 1 param
    Console.ReadLine();
}

public static void TestOptional(string A, int B = 0, params string[] C)
{
    Console.WriteLine(A);
    Console.WriteLine(B);
    Console.WriteLine(C.Count());
}   
4

3 回答 3

45

您现在唯一的选择是重载 TestOptional(就像您在 C# 4 之前必须做的那样)。不是首选,但它会在使用时清理代码。

public static void TestOptional(string A, params string[] C)
{
    TestOptional(A, 0, C);
}

public static void TestOptional(string A, int B, params string[] C)
{
    Console.WriteLine(A);
    Console.WriteLine(B);
    Console.WriteLine(C.Count());
}
于 2011-02-09T20:15:19.220 回答
17

尝试

TestOptional("A", C: new []{ "D", "E"});
于 2010-10-16T12:58:48.893 回答
13

这对我有用:

    static void Main(string[] args) {

        TestOptional("A");
        TestOptional("A", 1);
        TestOptional("A", 2, "C1", "C2", "C3"); 

        TestOptional("A", B:2); 
        TestOptional("A", C: new [] {"C1", "C2", "C3"}); 

        Console.ReadLine();
    }

    public static void TestOptional(string A, int B = 0, params string[] C) {
        Console.WriteLine("A: " + A);
        Console.WriteLine("B: " + B);
        Console.WriteLine("C: " + C.Length);
        Console.WriteLine();
    }
于 2012-12-10T19:39:01.707 回答