我有三个表,结构如下:
http://dl.dropbox.com/u/2586403/ORMIssues/TableLayout.png
我正在处理的三个对象在这里:
http://dl.dropbox.com/u/2586403/ORMIssues/Objects.zip
我需要能够获取一个 PartObject,然后拉取它的所有属性,按 Types 表中的 AttributeName 排序。以下是我遇到的问题:
我无法通过其 Attribute.AttributeName 属性对 PartObject 中的 Attributes 属性进行排序
我无法将 Attribute.AttributeName 属性添加到 ObjectAttribute 实体,因为我收到有关列名的错误。Hibernate 将 ID 放在连接的错误一侧
这是显示错误查询的休眠日志文件
10/14 16:36:39 [jrpp-12] HIBERNATE DEBUG - select objectattr0_.ID as ID1116_, objectattr0_.AttributeValue as Attribut2_1116_, objectattr0_.AttributeID as Attribut3_1116_, objectattr0_1_.AttributeName as Attribut2_1117_ from ObjectAttributes objectattr0_ inner join Attributes objectattr0_1_ on objectattr0_.ID=objectattr0_1_.AttributeID
10/14 16:36:39 [jrpp-12] HIBERNATE ERROR - [Macromedia] [SQLServer JDBC Driver][SQLServer]Invalid column name 'AttributeID'.
10/14 16:36:39 [jrpp-12] HIBERNATE ERROR - [Macromedia] [SQLServer JDBC Driver][SQLServer]Statement(s) could not be prepared.
这是查询的违规部分:
from ObjectAttributes objectattr0_
inner join Attributes objectattr0_1_ on objectattr0_.ID=objectattr0_1_.AttributeID
它应该是:
from ObjectAttributes objectattr0_
inner join Attributes objectattr0_1_ on objectattr0_.AttributeID=objectattr0_1_.ID
ObjectAttribute.cfc 上的 AttributeName 属性是导致问题的原因:
component output="false" persistent="true" table="ObjectAttributes"
{
property name="ID" column="ID" generator="native" type="numeric" ormtype="int" fieldtype="id" unsavedvalue="0" ;
property name="AttributeValue" type="string" ;
property name="Attribute" fieldtype="many-to-one" cfc="Attribute" fkcolumn="AttributeID" fetch="join";
property name="AttributeName" table="Attributes" joincolumn="AttributeID" ;
}
我还尝试使用公式来获取 ObjectAttribute 实体上的 AttributeName,如下所示:
component output="false" persistent="true" table="ObjectAttributes"
{
property name="ID" column="ID" generator="native" type="numeric" ormtype="int" fieldtype="id" unsavedvalue="0" ;
property name="AttributeValue" type="string" ;
property name="Attribute" fieldtype="many-to-one" cfc="Attribute" fkcolumn="AttributeID" fetch="join";
property name="AttributeName" type="string" formula="(SELECT A.AttributeName FROM Attributes A WHERE A.ID = AttributeID)";
}
这有效,但我无法按该计算列排序。如果我然后像这样调整 PartObject.cfc :
property name="Attributes" cfc="ObjectAttribute" type="array" fkcolumn="ObjectID" fieldtype="one-to-many" orderby="AttributeName";
我在 hibernatesql 日志中收到以下错误:
10/17 16:51:55 [jrpp-0] HIBERNATE DEBUG - select attributes0_.ObjectID as ObjectID2_, attributes0_.ID as ID2_, attributes0_.ID as ID244_1_, attributes0_.AttributeValue as Attribut2_244_1_, attributes0_.AttributeID as Attribut3_244_1_, ((SELECT A.AttributeName FROM Attributes A WHERE A.ID = attributes0_.AttributeID)) as formula25_1_, attribute1_.ID as ID246_0_, attribute1_.AttributeName as Attribut2_246_0_ from ObjectAttributes attributes0_ left outer join Attributes attribute1_ on attributes0_.AttributeID=attribute1_.ID where attributes0_.ObjectID=? order by attributes0_.AttributeName
10/17 16:51:55 [jrpp-0] HIBERNATE ERROR - [Macromedia][SQLServer JDBC Driver][SQLServer]Invalid column name 'AttributeName'.
10/17 16:51:55 [jrpp-0] HIBERNATE ERROR - [Macromedia][SQLServer JDBC Driver][SQLServer]Statement(s) could not be prepared.
这是一个没有该属性的转储,以表明其余关系正常工作:
http://dl.dropbox.com/u/2586403/ORMIssues/Dump.pdf
我不知道如何解决这个问题。您能提供的任何帮助将不胜感激。
谢谢,
担