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我正在我指定的目录中创建一个文件。我希望为每次运行在具有不同文件名的目录中创建一个不同的文件夹名称。这个文件夹应该被压缩。

目前我正在使用:

create or replace
PROCEDURE xx_WriteBLOBToFILE (myfilename IN VARCHAR2,L_PERSON_ID IN NUMBER) IS 

  v_blob         BLOB;
  blob_length    INTEGER;
    out_file utl_file.file_type;
  v_buffer       RAW(32767);
  chunk_size     BINARY_INTEGER := 32767;
  blob_position  INTEGER := 1;

BEGIN

  -- Retrieve the BLOB for reading
  Select Image Into V_Blob From Per_Images 
  Where Parent_Id =L_PERSON_ID;

  -- Retrieve the SIZE of the BLOB
  blob_length:=DBMS_LOB.GETLENGTH(v_blob);

  -- Open a handle to the location where you are going to write the BLOB to file
  -- NOTE: The 'wb' parameter means "write in byte mode" and is only availabe
  --       in the UTL_FILE package with Oracle 10g or later
  out_file := UTL_FILE.FOPEN ('INTF_DIR1', myfilename, 'wb', chunk_size);

  -- Write the BLOB to file in chunks 
  WHILE blob_position <= blob_length LOOP
    IF blob_position + chunk_size - 1 > blob_length THEN
      chunk_size := blob_length - blob_position + 1;
    END IF;
    DBMS_LOB.READ(v_blob, chunk_size, blob_position, v_buffer);
    UTL_FILE.PUT_RAW(out_file, v_buffer, TRUE);
    blob_position := blob_position + chunk_size;
  END LOOP;

  -- Close the file handle
  UTL_FILE.FCLOSE (out_file);
END;

这段代码将 blob 图像移动到目录中的文件夹。我希望在一个单独的文件夹中生成这个 blob 图像,该文件夹将在一个压缩文件夹下

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1 回答 1

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请参阅本讨论结尾处 指向az_zip包的链接使用 Oracle 存储过程的 Zip

https://technology.amis.nl/wp-content/uploads/2010/06/as_zip10.txt

于 2016-11-11T19:27:11.360 回答