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我有一个 ANT 目标，它在同一源代码上运行 findbugs 两次以生成 xml 和 html 报告

<delete dir="${findbugs.dir}"/>
<mkdir dir="${findbugs.dir}"/>        
<findbugs 
    home="${findbugs.home}"
    output="xml"
    outputFile="${findbugs.dir}/findbugs.xml"
    jvmargs="${findbugs.jvmargs}"
    timeout="${findbugs.timeout}"
    effort="${findbugs.effort}">
   <sourcePath path="${src.dir}"/>
   <class location="${build.classes.dir}"/>
</findbugs>

<findbugs 
    home="${findbugs.home}"
    output="html"
    outputFile="${findbugs.dir}/findbugs.html"
    jvmargs="${findbugs.jvmargs}"
    timeout="${findbugs.timeout}"
    effort="${findbugs.effort}">
   <sourcePath path="${src.dir}"/>
   <class location="${build.classes.dir}"/>
</findbugs>

这是愚蠢的，因为可以使用 xml 报告生成 html 报告

<xslt in="${findbugs.dir}/findbugs.xml" out="${findbugs.dir}/findbugs.html" style="${findbugs.home}/default.xsl"/>

但生成的 html 报告没有正确的源代码引用。关于如何使其正常工作并避免重复的 findbugs 调用的任何想法？

回答后更新

with output="xml"

<BugInstance type="REC_CATCH_EXCEPTION" priority="2" abbrev="REC" category="STYLE">
   <Class classname="com.x.y.aggregate.AggregationProperties">
      <SourceLine classname="com.x.y.aggregate.AggregationProperties" start="20" end="788" sourcefile="AggregationProperties.java" sourcepath="com/x/y/aggregate/AggregationProperties.java"/>
   </Class>
   <Method classname="com.x.y.aggregate.AggregationProperties" name="setAggregateProperties" signature="()V" isStatic="true">
      <SourceLine classname="com.x.y.aggregate.AggregationProperties" start="86" end="148" startBytecode="0" endBytecode="489" sourcefile="AggregationProperties.java" sourcepath="com/x/y/aggregate/AggregationProperties.java"/>
   </Method>
   <SourceLine classname="com.x.y.aggregate.AggregationProperties" start="140" end="140" startBytecode="308" endBytecode="308" sourcefile="AggregationProperties.java" sourcepath="com/x/y/aggregate/AggregationProperties.java"/>
</BugInstance>

with 'xml:withMessages'

<BugInstance type="REC_CATCH_EXCEPTION" priority="2" abbrev="REC" category="STYLE" instanceHash="b7a7c8f292d2a8432680a1c971fb93b3" instanceOccurrenceNum="0" instanceOccurrenceMax="0">
   <ShortMessage>Exception is caught when Exception is not thrown</ShortMessage>
   <LongMessage>Exception is caught when Exception is not thrown in com.x.y.aggregate.AggregationProperties.setAggregateProperties()</LongMessage>
   <Class classname="com.x.y.aggregate.AggregationProperties" primary="true">
      <SourceLine classname="com.x.y.aggregate.AggregationProperties" start="20" end="788" sourcefile="AggregationProperties.java" sourcepath="com/x/y/aggregate/AggregationProperties.java" relSourcepath="com/x/y/aggregate/AggregationProperties.java">
         <Message>At AggregationProperties.java:[lines 20-788]</Message>
      </SourceLine>
      <Message>In class com.x.y.aggregate.AggregationProperties</Message>
   </Class>
   <Method classname="com.x.y.aggregate.AggregationProperties" name="setAggregateProperties" signature="()V" isStatic="true" primary="true">
      <SourceLine classname="com.x.y.aggregate.AggregationProperties" start="86" end="148" startBytecode="0" endBytecode="489" sourcefile="AggregationProperties.java" sourcepath="com/x/y/aggregate/AggregationProperties.java" relSourcepath="com/x/y/aggregate/AggregationProperties.java"/>
      <Message>In method com.x.y.aggregate.AggregationProperties.setAggregateProperties()</Message>
   </Method>
   <SourceLine classname="com.x.y.aggregate.AggregationProperties" primary="true" start="140" end="140" startBytecode="308" endBytecode="308" sourcefile="AggregationProperties.java" sourcepath="com/x/y/aggregate/AggregationProperties.java" relSourcepath="com/x/y/aggregate/AggregationProperties.java">
      <Message>At AggregationProperties.java:[line 140]</Message>
   </SourceLine>
</BugInstance>
4

1 回答 1

2

output="xml:withMessages"

从文档中，

如果设置为“xml”（默认值），则输出为 XML 格式。如果设置为“xml:withMessages”，则输出为 XML 格式，并增加了人类可读的消息。（如果您计划使用 XSL 样式表生成报告，则应使用此格式。）

于 2011-04-18T16:46:36.997 回答