我正在使用带有OrientDb Studio 2.2.8的 Vehicle History 数据库，并且我想投影automobile由Kia.
数据库的架构如下所示：
(Automobile) --isModel--> (Model) --isMake--> (Make)
其中Automobile、Model和Make是顶点isModel， 和isMake是边类型。
我想使用traverse 语句返回一个等效的结果集，因为我从这个命令得到：
Select expand(in('isMake').in('isModel')) from Make where name = "Kia"
谁的结果是……
+----+--------+---------+---------+---------+---------+---------+---------+---------+---------+---------+
|# |@RID |@CLASS |color |convertib|out_isMod|trailerHi|emissions|safety |out_Purch|VIN |
+----+--------+---------+---------+---------+---------+---------+---------+---------+---------+---------+
|0 |#17:1441|Automo...|White |true |[#24:1...|false |2016-0...|2014-0...|[#23:5...|840CDC...|
|1 |#17:1576|Automo...|Maroon |true |[#24:1...|false |2010-0...|2004-0...|[#23:5...|E71761...|
|2 |#17:1503|Automo...|Dark Gray|true |[#24:1...|false |2009-0...|2016-1...|[#23:5...|FAEB6F...|
+----+--------+---------+---------+---------+---------+---------+---------+---------+---------+---------+
我试着运行这个：
Select
from (traverse in from Make while $depth <= 2)
where name = "Kia"
我只收到了一条记录，它不像我预期的那样属于汽车类。它来自 Make。
+----+-------+------+----+-------------------------------------+----------------------------+
|# |@RID |@CLASS|name|in_isMake |out_Sold |
+----+-------+------+----+-------------------------------------+----------------------------+
|0 |#15:612|Make |Kia |[#25:1767,#25:2036,#25:2067,#25:2131]|[#22:5153,#22:5383,#22:5655]|
+----+-------+------+----+-------------------------------------+----------------------------+
基本上，我想使用 Traverse 开始Make在数据库中投影三辆起亚汽车。