3

我正在制作一个 Anuglar2 rc-4 Web 应用程序。我正在尝试限制路由，但是当我添加登录保护时，它告诉我没有提供程序。我的正常登录服务代码工作正常，就在我尝试添加登录保护和 canActive 路由时。有关如何解决此错误的任何想法？

路线.ts

import { RouterConfig } from '@angular/router';
import { Home } from './components/home/home';
import { Login } from './components/login/login';
import { DashBoard } from './components/dashboard/dashboard';
import { User } from './components/user/user';
import { Store } from './components/store/store';
import { LoggedInGuard } from './models/logged-in.guard.ts'; 

export const routes: RouterConfig = [
    { path: '', redirectTo: 'home', pathMatch: 'full' },
    { path: 'home', component: Home, canActivate: [LoggedInGuard] },
    { path: 'login', component: Login },
    { path: 'dashboard', component: DashBoard },
    { path: 'user', component: User },
    { path: 'store', component: Store },
    { path: '**', redirectTo: 'home' }
];

引导.ts

import { bootstrap } from '@angular/platform-browser-dynamic';
import { FormBuilder } from '@angular/common';
import { provideRouter } from '@angular/router';
import { HTTP_PROVIDERS, JSONP_PROVIDERS } from '@angular/http';
import { App } from './components/app/app';
import { routes } from './routes';

bootstrap(App, [
    HTTP_PROVIDERS,
    FormBuilder,
    provideRouter(routes)
]);

登录的.guard.ts

import { Injectable } from '@angular/core';
import { Router, CanActivate } from '@angular/router';
import { LoginService } from '../services/login.service';

@Injectable()
export class LoggedInGuard implements CanActivate {
  constructor(private ls: LoginService) {}

  canActivate() {
    return this.ls.isLoggedIn();
  }
}
4

1 回答 1

4

您必须LoggedInGuard在应用程序引导函数中注入您的服务

bootstrap(App, [
    HTTP_PROVIDERS,
    FormBuilder,
    provideRouter(routes),
    LoggedInGuard // injected LoggedInGuard service provider here
]);

注意：对于当前的 angular 2 更新版本（rc.6），此答案将不一样，当您升级时，您需要创建一个 NgModule将所有依赖项包装在一个地方的位置，该时间LoggedInGuard将进入providers选项`NgModule 的

`

于 2016-09-05T20:58:38.937 回答