我正在使用 pyqt 制作指南,并且包含一个 ipython qtconsole 小部件。
try:
from qtconsole.rich_jupyter_widget import RichJupyterWidget as ipythonWidget
from qtconsole.inprocess import QtInProcessKernelManager
except:
from IPython.qt.console.rich_ipython_widget import RichIPythonWidget as ipythonWidget
from IPython.qt.inprocess import QtInProcessKernelManager
我想从我的代码中修改 qtconsole 输入但不工作。我已经尝试了 set_next_input 函数,但它不起作用,我找不到另一个可以用来完成我想要的函数。甚至有可能实现我想要的吗?如果是这样,我该怎么做?
这是我的代码:
try:
from qtconsole.rich_jupyter_widget import RichJupyterWidget as ipythonWidget
from qtconsole.inprocess import QtInProcessKernelManager
except:
from IPython.qt.console.rich_ipython_widget import RichIPythonWidget as ipythonWidget
from IPython.qt.inprocess import QtInProcessKernelManager
import sys
from PyQt4 import QtGui
class sympyIpython(QtGui.QWidget):
def __init__(self):
super().__init__()
self.ipython = IpythonWidget()
v = QtGui.QVBoxLayout(self)
button = QtGui.QPushButton('append to input')
v.addWidget(self.ipython)
v.addWidget(button)
button.clicked.connect(self.symClicked)
def symClicked(self):
self.ipython.kernel.shell.set_next_input(' appended text')
class IpythonWidget(ipythonWidget):
def __init__(self):
super().__init__()
self.kernel_manager = QtInProcessKernelManager()
self.kernel_manager.start_kernel()
self.kernel = self.kernel_manager.kernel
self.kernel.gui = 'qt4'
self.kernel_client = self.kernel_manager.client()
self.kernel_client.start_channels()
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
m = sympyIpython()
m.show()
sys.exit(app.exec_())