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我有一个具有正值的数组。例如 array= {5,4,4,3.8,2,1.7} 我需要找到一个总和最大但小于 12 的子数组。在这种情况下，它将是 {4,4,3.8}

另一个 ex 数组 {7,4,3,2} 在这种情况下，最大总和为 12，子集为 {7,3,2}

它的算法是什么，因为我有一个长度超过 1000 的非常大的数组。我正在用 VBA excel 编写这个程序。

谢谢。

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2 回答 2

2

试试这个算法的子序列

Sub aargh()
Dim a As Variant
Dim limsum As Double, highestnum As Double
Dim i As Integer, j As Integer
    a = Array(5, 4, 4, 3.8, 2, 1.7)
    limsum = 12

    highestsum = 0
    For i = 0 To UBound(a)
        s = a(i)
        j = i
        Do
            If s > highestsum Then fs = i: ls = j: highestsum = s
            j = j + 1
            If j > UBound(a) Then Exit Do
            s = s + a(j)
        Loop While s <= limsum
    Next i
    MsgBox "subarray (" & fs & "," & ls & ") sum = " & highestsum
End Sub

编辑以包括以下备注并包括子集的解决方案

Sub aargh()

    Dim sol(), csol()
    a = Array(7, 4, 3, 2)

    ReDim sol(LBound(a) To UBound(a))
    ReDim csol(LBound(a) To UBound(a))
    limsum = 13
    findsum a, sol, csol, maxsum, limsum
    ss = "array "
    For i = 1 To sol(0)
        ss = ss & sep & a(sol(i))
        sep = ","
    Next i
    MsgBox ss & " sum =" & maxsum
End Sub
Sub findsum(ByRef a, ByRef sol, ByRef csol, ByRef maxsum, ByRef limsum, Optional s = 0, Optional lvl = 1, Optional si = 0)
' recursive sub
    For i = si To UBound(a)
        s = s + a(i)
        csol(lvl) = i ' current solution contains number i
        If s <= limsum Then
            If s > maxsum Then ' we found a sum greater than current max we save it
                maxsum = s
                sol(0) = lvl
                For j = 1 To lvl
                    sol(j) = csol(j)
                Next j
            End If
            If i < UBound(a) Then ' pick another number
                findsum a, sol, csol, maxsum, limsum, s, lvl + 1, i + 1
            End If
        End If
        s = s - a(i)
    Next i
End Sub

如果数组已排序（降序），则代码优化

Sub aargh()

    Dim sol(), csol()
    a = Array(20, 15, 10, 7, 6, 5, 4, 3, 2)

    ReDim sol(LBound(a) To UBound(a))
    ReDim csol(LBound(a) To UBound(a))
    limsum = 13
    findsum a, sol, csol, maxsum, limsum, UBound(a)
    ss = "array "
    For i = 1 To sol(0)
        ss = ss & sep & a(sol(i))
        sep = ","
    Next i
    MsgBox ss & " sum =" & maxsum
End Sub
Sub findsum(ByRef a, ByRef sol, ByRef csol, ByRef maxsum, ByRef limsum, si, Optional s = 0, Optional lvl = 1)
' recursive sub
    For i = si To LBound(a) Step -1
        If s + a(i) > limsum Then Exit For
        s = s + a(i)
        csol(lvl) = i    ' current solution contains number i
        If s <= limsum Then
            If s > maxsum Then    ' we found a sum greater than current max we save it
                maxsum = s
                sol(0) = lvl
                For j = 1 To lvl
                    sol(j) = csol(j)
                Next j
            End If
            If i > LBound(a) Then    ' pick another number
                findsum a, sol, csol, maxsum, limsum, i - 1, s, lvl + 1
            End If
        End If
        s = s - a(i)
        If maxsum = limsum Then Exit For 'exit if exact match
    Next i
End Sub
于 2016-09-02T17:39:17.093 回答
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正如多人在评论中提到的那样，这是子集和问题的简单变体。为了解决这个确切的问题，你只需要记住你发现的小于或等于的最大数12。

一个简单的递归abroach如下：

list = [...]
N = length of list
dp[ maximum possible sum ][ N ]

f(‌current_sum, index):
  if dp[current_sum][index] is set
    return dp[current_sum][index]
  if index >= N
    if current_sum > 12
       result = 0
    else
       result = current_sum
  else
    result = max( f(current_sum, index+1), f(current_sum+list[index], index+1)
  dp[current_sum][index] = result
  return result

result = f(0,0) // this will return the desired result
于 2016-09-02T19:19:35.400 回答