2

我有一组字符串，我需要按中间有句点的单词进行搜索。一些字符串是连接的，所以我需要将它们分成单词，以便我可以过滤带有点的单词。

以下是我所拥有的以及到目前为止所获得的示例

 punctToRemove <- c("[^[:alnum:][:space:]._]")

 s <- c("get_degree('TITLE',PERS.ID)",
        "CLIENT_NEED.TYPE_CODe=21",
        "2.1.1Report Field Level Definition",
        "The user defined field. The user will validate")

这是我目前得到的

gsub(punctToRemove, " ", s)

[1] "get_degree  TITLE  PERS.ID "                   
[2] "CLIENT_NEED.TYPE_CODe 21"                      
[3] "2.1.1Report Field Level Definition"            
[4] "The user defined field. The user will validate"

我想要的样本如下

[1] "get_degree ( ' TITLE ' , PERS.ID ) "          # spaces before and after the "(", "'", ",",and ")"
[2] "CLIENT_NEED.TYPE_CODe = 21"                   # spaces before and after the "=" sign. Dot and underscore remain untouched.        
[3] "2.1.1Report Field Level Definition"           # no changes 
[4] "The user defined field. The user will validate" # no changes
4

2 回答 2

2

我们可以使用正则表达式环视

s1 <- gsub("(?<=['=(),])|(?=['(),=])", " ", s, perl = TRUE)
s1
#[1] "get_degree ( ' TITLE ' , PERS.ID ) "           
#[2] "CLIENT_NEED.TYPE_CODe = 21"                    
#[3] "2.1.1Report Field Level Definition"            
#[4] "The user defined field. The user will validate"

nchar(s1)
#[1] 35 26 34 46

这等于 OP 的预期输出中显示的字符数。

于 2016-09-01T15:24:04.163 回答
0

对于这个例子：

   library(stringr)
    s <- str_replace_all(s, "\\)", " \\) ")
    s <- str_replace_all(s, "\\(", " \\( ")
    s <- str_replace_all(s, "=", " = ")
    s <- str_replace_all(s, "'", " ' ")
    s <- str_replace_all(s, ",", " , ")
于 2016-09-01T15:23:33.913 回答