是否可以使用 Spin 获得多个(或全部)违规跟踪?
例如,我在下面创建了 Promela 模型:
byte mutex = 0;
active proctype A() {
A1: mutex==0; /* Is free? */
A2: mutex++; /* Get mutex */
A3: /* A's critical section */
A4: mutex--; /* Release mutex */
}
active proctype B() {
B1: mutex==0; /* Is free? */
B2: mutex++; /* Get mutex */
B3: /* B's critical section */
B4: mutex--; /* Release mutex */
}
ltl {[] (mutex < 2)}
它有一个简单的互斥锁实现。可以预期进程 A 和 B 不会一起到达它们的临界区,我编写了一个 LTL 表达式来检查这一点。
跑步
spin -run mutex_example.pml
表明该属性无效且正在运行
spin -p -t mutex_example.pml
显示违反该属性的语句序列。
Never claim moves to line 4 [(1)]
2: proc 1 (B:1) mutex_example.pml:11 (state 1) [((mutex==0))]
4: proc 0 (A:1) mutex_example.pml:4 (state 1) [((mutex==0))]
6: proc 1 (B:1) mutex_example.pml:12 (state 2) [mutex = (mutex+1)]
8: proc 0 (A:1) mutex_example.pml:5 (state 2) [mutex = (mutex+1)]
spin: _spin_nvr.tmp:3, Error: assertion violated
spin: text of failed assertion: assert(!(!((mutex<2))))
Never claim moves to line 3 [assert(!(!((mutex<2))))]
spin: trail ends after 9 steps
#processes: 2
mutex = 2
9: proc 1 (B:1) mutex_example.pml:14 (state 3)
9: proc 0 (A:1) mutex_example.pml:7 (state 3)
9: proc - (ltl_0:1) _spin_nvr.tmp:2 (state 6)
这表明语句序列(由标签指示)'B1' -> 'A1' -> 'B2' -> 'A2' 违反了该属性,但还有其他交错选项导致该属性(例如 'A1' -> ' B1'->'B2'->'A2')。
我可以要求 Spin 给我多条(或全部)痕迹吗?