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在闪亮的应用程序中将两者合二为一时，迷你图会混淆rhandsontables。tabPanel第一个表的迷你图显示正确，而第二个表包含与第一个表相同的迷你图，反之亦然。但是，如果在不同的 tabPanel 中“绘制”，它们就好了。

有没有办法将两者rhandsontables合二为一tabPanel？

这是我的代码：

library(shiny)
library(dplyr)
library(rhandsontable)

#example data set1
dat1 <- data.frame(a=sample(1:10, 10), b=sample(1:10, 10), c=sample(1:10, 10),  d=sample(1:10, 10),  e=sample(1:10, 10))
dat1$a1 <- sapply(1:nrow(dat1), function(x) jsonlite::toJSON(list(values=c(as.numeric(dat1$a[x]), as.numeric(dat1$b[x]), as.numeric(dat1$c[x]), as.numeric(0)), options = list(type = "line"))))

dat1$a2 <- sapply(1:nrow(dat1), function(x) jsonlite::toJSON(list(values=c(as.numeric(dat1$d[x]), as.numeric(dat1$e[x]), as.numeric(0)), options = list(type = "line"))))

#example data set1
dat2 <- data.frame(a=sample(1:10, 10), b=sample(1:10, 10), c=sample(1:10, 10),  d=sample(1:10, 10),  e=sample(1:10, 10))
dat2$a1 <- sapply(1:nrow(dat2), 
              function(x) jsonlite::toJSON(list(values=c(as.numeric(dat2$a[x]), as.numeric(dat2$b[x]), as.numeric(dat2$c[x]), as.numeric(0)), options = list(type = "bar"))))
dat2$a2 <- sapply(1:nrow(dat2),
              function(x) jsonlite::toJSON(list(values=c(as.numeric(dat2$d[x]), as.numeric(dat2$e[x]), as.numeric(0)), options = list(type = "bar"))))



runApp(launch.browser = TRUE, 
   list(ui=shinyUI(fluidPage(

     titlePanel("MYTITLE"),
     mainPanel(
       tabPanel("A",
                rHandsontableOutput("first"),
                br(),
                rHandsontableOutput("second"))

     )
   )),
     server = function(input, output) {

       output$first <- renderRHandsontable({
       dat1 %>%
         select(a, b, c, a1, d, e, a2)%>%
         rhandsontable(readOnly = TRUE, width = 800, 
                       allowedTags = "<em><b><span><strong><a><big>") %>%
         hot_cols(colWidths = c(50, 50, 50,80, 50, 50, 80)) %>%
         hot_col("a", format = "0")%>%
         hot_col("b", format = "0") %>%
         hot_col("c", format = "0") %>%
         hot_col("d", format = "0") %>%
         hot_col("e", format = "0") %>%
         hot_col("a1", renderer = htmlwidgets::JS("renderSparkline")) %>%
         hot_col("a2", renderer = htmlwidgets::JS("renderSparkline")) %>%
         hot_table(highlightCol = TRUE, highlightRow = TRUE) 
       })

       output$second <- renderRHandsontable({
         dat2 %>%
           select(a, b, c, a1, d, e, a2)%>%
           rhandsontable(readOnly = TRUE, width = 800, 
                         allowedTags = "<em><b><span><strong><a><big>") %>%
           hot_cols(colWidths = c(50, 50, 50,80, 50, 50, 80)) %>%
           hot_col("a", format = "0")%>%
           hot_col("b", format = "0") %>%
           hot_col("c", format = "0") %>%
           hot_col("d", format = "0") %>%
           hot_col("e", format = "0") %>%
           hot_col("a1", renderer = htmlwidgets::JS("renderSparkline")) %>%
           hot_col("a2", renderer = htmlwidgets::JS("renderSparkline")) %>%
           hot_table(highlightCol = TRUE, highlightRow = TRUE) 
       })

     }
   )
)

任何帮助表示赞赏，谢谢！

4

1 回答 1

1

这是一个有点笨拙和肮脏的解决方案——我相信有一种正确的方法！但是问题似乎出现了，因为span class在两个表中都指向相同的名称（例如span class="sparklines_r0_c3"）。因此，一种解决方法是让迷你图在每个表的不同列中出现。我向第一个数据框添加一NA列：

dat1$x <- NA

然后在第一个表中插入一个 1 像素宽的空白列：

output$first <- renderRHandsontable({
dat1 %>%
 select(x, a, b, c, a1, c, d, e, a2)%>%
 rhandsontable(readOnly = TRUE, width = 801, 
               allowedTags = "<em><b><span><strong><a><big>") %>%
 hot_cols(colWidths = c(1, 50, 50, 50,80, 50, 50, 80)) %>%
 hot_col("a", format = "0")%>%
 hot_col("b", format = "0") %>%
 hot_col("c", format = "0") %>%
 hot_col("d", format = "0") %>%
 hot_col("e", format = "0") %>%
 hot_col("a1", renderer = htmlwidgets::JS("renderSparkline")) %>%
 hot_col("a2", renderer = htmlwidgets::JS("renderSparkline")) %>%
 hot_table(highlightCol = TRUE, highlightRow = TRUE) 
})

输出：

在此处输入图像描述

于 2016-08-25T22:33:13.800 回答