php - 内联键盘。我做了一个按钮，但是如何处理 callback_data 呢？

Question

需要内联键盘方面的帮助。我做了一个按钮，但是回调怎么办？我知道我需要以某种方式获取callback_data并发出一条新消息。

     <?php
$access_token = 'xxx';
$api = 'https://api.telegram.org/bot' . $access_token;
$output = json_decode(file_get_contents('php://input'), TRUE);
$chat_id = $output['message']['chat']['id'];
$first_name = $output['message']['chat']['first_name'];
$message = $output['message']['text'];
$callback_query = $output['callback_query'];
$data = $callback_query['data'];
$message_id = ['callback_query']['message']['message_id'];
switch($message) {
    case '/test':  
    $inline_button1 = array("text"=>"Google url","url"=>"http://google.com");
    $inline_button2 = array("text"=>"work plz","callback_data"=>'/plz');
    $inline_keyboard = [[$inline_button1,$inline_button2]];
    $keyboard=array("inline_keyboard"=>$inline_keyboard);
    $replyMarkup = json_encode($keyboard); 
     sendMessage($chat_id, "ok", $replyMarkup);
    break;
}
switch($data){
    case '/plz':
    sendMessage($chat_id, "plz");
    break;
}
function sendMessage($chat_id, $message, $replyMarkup) {
  file_get_contents($GLOBALS['api'] . '/sendMessage?chat_id=' . $chat_id . '&text=' . urlencode($message) . '&reply_markup=' . $replyMarkup);
}

Answer 1

如果有人单击该按钮，您将收到一个callback_query对象而不是消息对象。callback_query 本身包含最初发送的消息。

$output = json_decode(file_get_contents('php://input'), TRUE);
$callback_query = $output["callback_query"]
$data = $callback_query["data"] // in your case $data is "/plz"