javascript - 在选择中为 ng-model 分配一个对象

Question

我正在迭代一个范围并为每个索引填充新的选择选项。这些选项与我正在迭代的范围无关，而是不同类型的选项。代码如下：

<div ng-repeat="i in range(booking.numberOfRooms) track by $index">
    <p>Room {{$index + 1}}</p>
    <select ng-model="booking.roomSelection[$index]" ng-options="obj.roomType as obj.roomType for obj in roomTypes" ng-init="booking.roomSelection[$index] = { id: $index + 1, roomType: 'Double' }"> </select>
</div>

如何将对象数组分配给 ng-model（就像 ng-init 中的那样）？例如，对于两个房间，ng-model 的结果应该类似于：

booking.roomSelection = [{id: 1, roomSelection: 'Double'}, {id: 2, roomSelection: 'Double'}]

Answer 1

只需绑定到您booking.roomSelection并删除. 如ng-init​​果您选择两个选项，它们的值将pushed进入booking.roomSelection并且booking.roomSelection将是一个数组

<select multiple ng-model="booking.roomSelection" ng-options="obj.roomType as obj.roomType for obj in roomTypes"></select>

Answer 2

原来 ng-model 属性必须更改为：booking.roomSelection[$index].roomType

对象数组也必须在控制器中声明，例如$scope.booking.roomSelection = [];

完整的声明是：

<div ng-repeat="i in range(booking.numberOfRooms) track by $index">
    <p>Room {{$index + 1}}</p>
    <select ng-model="booking.roomSelection[$index].roomType" ng-options="obj.roomType as obj.roomType for obj in roomTypes" ng-init="booking.roomSelection[$index] = { id: $index + 1, roomType: 'Double' }"></select>
</div>