MySQL 服务器版本:5.1.73 源代码分发。
我无法创建函数,删除后它仍然存在。
先删除函数:
mysql> drop function if exists `xapps_f20160817`; Query OK, 0 rows affected, 1 warning (0.00 sec) mysql> show warnings; +-------+------+-----------------------------------------+ | Level | Code | Message | +-------+------+-----------------------------------------+ | Note | 1305 | FUNCTION xapps_f20160817 does not exist | +-------+------+-----------------------------------------+ 1 row in set (0.00 sec)
但是当我再次创建它时它仍然存在。
mysql> create function `xapps_f20160817`( -> `_time` varchar(30), -> `_rpid` varchar(10), -> `_mvsz` varchar(10), -> `_rvsz` varchar(10), -> `_ncpu` varchar(10), -> `_rcpu` varchar(10), -> `_appn` varchar(64) -> ) RETURNS BIGINT READS SQL DATA -> BEGIN -> insert into `20160817`(time, rpid, mvsz, rvsz, ncpu, rcpu, appn) -> values(_time, _rpid, _mvsz, _rvsz, _ncpu, _rcpu, _appn); -> RETURN LAST_INSERT_ID(); -> END ERROR 1304 (42000): FUNCTION xapps_f20160817 already exists
尝试使用:
mysql> select xapps_f20160817('100','100','100','100','100','100','100');$$ ERROR 1305 (42000): FUNCTION xapps_db.xapps_f20160817 does not exist
尝试从函数列表中找到它:
mysql> show function status where name='xapps_f20160817';$$ Empty set (0.00 sec)
尝试删除它,但它不存在:
mysql> drop function if exists `xapps_f20160817`;$$ Query OK, 0 rows affected, 1 warning (0.00 sec) mysql> show warnings;$$ +-------+------+-----------------------------------------+ | Level | Code | Message | +-------+------+-----------------------------------------+ | Note | 1305 | FUNCTION xapps_f20160817 does not exist | +-------+------+-----------------------------------------+ 1 row in set (0.01 sec)
它是MySQL的错误吗?如何正确删除此功能?