我有以下 CXF 配置类:
package de.wps.ztr.config;
import org.apache.cxf.Bus;
import org.apache.cxf.bus.spring.SpringBus;
import org.apache.cxf.jaxws.EndpointImpl;
import org.apache.cxf.ws.policy.attachment.external.PolicyAttachment;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.context.annotation.Profile;
import javax.xml.ws.Endpoint;
@Configuration
public class CxfConfig {
@Bean(name = Bus.DEFAULT_BUS_ID)
public SpringBus springBus() {
final SpringBus springBus = new SpringBus();
return springBus;
}
@Bean
public MyService myService() {
return new MyService();
}
@Bean
public Endpoint myServiceEndpoint() {
final EndpointImpl endpoint = new EndpointImpl(springBus(), MyService());
endpoint.publish("...");
return endpoint;
}
}
它配置 CXF 总线并发布端点。我想为该端点配置 WS Policy。该策略在外部文件中定义。这里解释了如何使用 XML 配置文件来实现这一点:
这是来自 CXF 网站的示例:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:jaxws="http://cxf.apache.org/jaxws"
xmlns:cxf="http://cxf.apache.org/core"
xmlns:p="http://cxf.apache.org/policy"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://cxf.apache.org/core http://cxf.apache.org/schemas/core.xsd
http://cxf.apache.org/policy http://cxf.apache.org/schemas/policy.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd"
http://cxf.apache.org/jaxws http://cxf.apache.org/schemas/jaxws.xsd">
<jaxws:endpoint id="CRMService"
xmlns:serviceNamespace="http://services.talend.org/CRMService"
serviceName="serviceNamespace:CRMServiceProvider"
endpointName="serviceNamespace:CRMServicePort"
implementor="#CRMServiceBean"
address="/CRMServiceProvider">
<jaxws:features>
<p:policies>
<wsp:PolicyReference xmlns:wsp="http://www.w3.org/ns/ws-policy" URI="classpath:/saml.policy"/>
</p:policies>
</jaxws:features>
</jaxws:endpoint>
</beans>
问题是,我怎样才能使用 API 以编程方式做同样的事情?