public enum ReportStatus {
SUCCCEED, FAILED;
}
public class Work {
@ElementCollection
@Enumerated(EnumType.STRING)
List<ReportStatus> reportStatuses;
}
鉴于以下结构,我想执行查询以查找所有由 reportStatuses 过滤的工作。它适用于以下 hql 语法:
public List<Long> queryHQL() {
final String query = "SELECT w.id FROM Work w JOIN w.reportStatuses s WHERE s in (:rs)";
final List<ReportStatus> reportStatuses = new ArrayList<ReportStatus>();
reportStatuses.add(ReportStatus.FAILED);
return this.entityManager.createQuery(query).setParameter("rs", reportStatuses).getResultList();
}
但我想使用标准 API (jpa2),但不知道该怎么做。这是我认为的最接近的尝试:
public List<Long> query() {
final List<ReportStatus> reportStatuses = new ArrayList<ReportStatus>();
reportStatuses.add(ReportStatus.FAILED);
final CriteriaBuilder builder = this.entityManager.getCriteriaBuilder();
final CriteriaQuery<Long> criteriaQuery = builder.createQuery(Long.class);
final Root<Work> workModel = criteriaQuery.from(Work.class);
final ListJoin<Work, ReportStatus> status = workModel.joinList("reportStatuses");
final Predicate predicate = status.in(reportStatuses);
criteriaQuery.where(predicate);
criteriaQuery.select(workModel.<Long> get("id"));
return this.entityManager.createQuery(criteriaQuery).getResultList();
}
我也尝试过使用休眠标准 API,但作为 jpa2 的 API,我找不到正确的语法。