php - 获取图像尺寸

Question

我有一个图片的网址，比如$var = http://example.com/image.png

我如何将其尺寸转换为数组，例如 array([h]=> 200, [w]=>100) (height=200, width=100)？

Answer 1

您可以getimagesize像这样使用该功能：

list($width, $height) = getimagesize('path to image');
echo "width: " . $width . "<br />";
echo "height: " .  $height;

Answer 2

使用getimagesize函数，我们还可以获得该特定图像的这些属性-

<?php

list($width, $height, $type, $attr) = getimagesize("image_name.jpg");

echo "Width: " .$width. "<br />";
echo "Height: " .$height. "<br />";
echo "Type: " .$type. "<br />";
echo "Attribute: " .$attr. "<br />";

//Using array
$arr = array('h' => $height, 'w' => $width, 't' => $type, 'a' => $attr);
?>

像这样的结果——

宽度：200
高度：100
类型：2
属性：width='200' height='100'

图像类型考虑像 -

1 = GIF
2 = JPG
3 = PNG
4 = SWF
5 = PSD
6 = BMP
7 = TIFF（英特尔字节顺序）
8 = TIFF（摩托罗拉字节顺序）
9 = JPC
10 = JP2
11 = JPX
12 = JB2
13 = SWC
14 = IFF
15 = WBMP
16 = XBM

Answer 3

<?php 
    list($width, $height) = getimagesize("http://site.com/image.png"); 
    $arr = array('h' => $height, 'w' => $width );
?>