1

我想对此模式执行查询:

{ 
   "name" : "xxx",
   "guests" : [ 
       {
            "category" : "category 1",
            "arrived" : false
       },
       {
            "category" : "category 2",
            "arrived" : false
       },
       {
            "category" : "category 1",
            "arrived" : true
       },
       {
            "category" : "category 2",
            "arrived" : true
       }
   ]
}

我想获取某个名称,一个包含每个类别的客人百分比的列表。

以上面的文件为例,我想收到:

{
    name : "xxx",
    results : [
         {
              category : "category 1",
              arrived : 50 (percent)
         },
         {
              category : "category 2",
              arrived : 50 (percent)
         },
    ]

有没有办法用单个 MongoDB 查询来做到这一点?另外,我应该在客户端还是服务器端进行计算?

4

1 回答 1

5

您可以使用聚合。这是一个例子:

[
    {
        $match: {name:"xxx"}
    },
    {
        $unwind: "$guests"
    },
    {
        $group: {
            _id:"$guests.category",
            guests_arrived: {
                $sum: { $cond: [ {$eq:["$guests.arrived",true]}, 1, 0 ] }
            },
            guests_total: {
                $sum: 1
            }
        }
    },
    {
        $project:{
            _id: false,
            category: "$_id",
            guests_arrived:true,
            guests_total:true,
            "percent": {
                $multiply: [
                    100,
                    {$divide: ["$guests_arrived","$guests_total"]}
                ]

            }
        }
    }
]

使用的聚合管道阶段的说明:

$match on name,因为您只需要特定名称的结果

$unwind客人数组,以便我们可以在下一阶段对其成员执行聚合函数

$group by category$sum总客人数和已到达客人数 $cond/$eq用于评估已到达,并且仅在到达=true时才添加到guest_arrived

$project的主要目的是根据上一阶段的汇总值guest_arrivedguest_total计算百分比

于 2016-08-11T08:52:40.623 回答