2

我有一个看起来像这样的类:

public class Item
{
    public Guid Id { get; set; }
    public Guid Parent { get; set; }
    public string Name { get; set; }
}

如果我序列化它:

        var parentId = Guid.NewGuid();
        var items = new List<Item>
        {
            new Item {Id = parentId, Parent = Guid.Empty, Name = "Parent"},
            new Item {Id = Guid.NewGuid(), Parent = parentId, Name = "Child"}
        };

        var builder = new StringBuilder();

        var serializer = new YamlDotNet.Serialization.Serializer();

        using (var writer = new StringWriter(builder))
        {
            serializer.Serialize(writer, items);
        }

        Console.WriteLine(builder.ToString());

输出是:

- Id: 1c49bc54-d0e3-494e-8fd7-b9ffd8c1892a
  Name: Parent
- Id: dd54864a-61f7-4d73-b89d-9bd4e4c2c8f4
  Parent: *o0
  Name: Child

创建了一个引用*o0,它是另一个类的 ID,它是它的父类。但是 YamlDotnet 没有定义这个引用,因此在反序列化时我得到一个错误,说它缺少一个锚。

这是框架中的错误还是我能做些什么?

4

0 回答 0