2

我有一个如下的 JSON 文件

{
      "boost_id": "75149",
      "content_id": "627680",
      "headline": "19 Rare Historical Photos That Will Leave You Breathless ",
      "target_url": "http://stars.americancolumn.com/2016/02/21/historical-photos/?full=1",
      "return": "district" 
 }

我需要将 json 字符串转换为 java 对象。由于“return”被称为 Java 保留关键字，因此无法形成带有返回变量的 Dto。

有没有其他方法可以使用保留变量并将上述 JSON 转换为 JAVA 对象。

下面是我的 Dto 结构，

public class RevcontentReportResponse {

    private String boost_id;
    private String content_id;
    private String headline;
    private String target_url;
//  private String return;

    public String getBoost_id() {
        return boost_id;
    }

    public void setBoost_id(String boost_id) {
        this.boost_id = boost_id;
    }

    public String getContent_id() {
        return content_id;
    }

    public void setContent_id(String content_id) {
        this.content_id = content_id;
    }

    public String getHeadline() {
        return headline;
    }

    public void setHeadline(String headline) {
        this.headline = headline;
    }

    public String getTarget_url() {
        return target_url;
    }

    public void setTarget_url(String target_url) {
        this.target_url = target_url;
    }
}

主要方法：

ObjectMapper mapper = new ObjectMapper();

File json = new File("historic.json");
RevcontentReportResponse cricketer = mapper.readValue(json, RevcontentReportResponse.class);
System.out.println("Java object created from JSON String :");
System.out.println(cricketer);
4

2 回答 2

3

Use the JsonProperty annotation:

@JsonProperty("return")
private String returnValue;

That said, JSON stands for JavaScript Object Notation, and return is also a JavaScript keyword (and it's the same for many other languages). You'd better change the name of the attribute in the JSON.

于 2016-08-06T10:32:29.453 回答
2

Just add a field with its getter/setter and annotate it with @JsonProperty("return").

于 2016-08-06T10:32:29.387 回答