5

我使用了 find contours 和 boundingrect 并将其显示在我的项目中。然后我想找到最大的轮廓并显示它。这可能吗？我是 OpenCV java lang 的新手。

到目前为止，这是我的代码：

@Override
public void onCameraViewStarted(int width, int height) {
    mRgba = new Mat(height, width, CvType.CV_8UC4);
    mHsv = new Mat(height,width,CvType.CV_8UC3);
    hierarchy = new Mat();
    mHsvMask = new Mat();
    mDilated = new Mat();
    mEroded = new Mat();
}

@Override
public void onCameraViewStopped() {
    mRgba.release();
    mHsv.release();
    mHsvMask.release();
    mDilated.release();
    hierarchy.release();

}

@Override
public Mat onCameraFrame(CameraBridgeViewBase.CvCameraViewFrame inputFrame) {

    mRgba =inputFrame.rgba();
    contours = new ArrayList<MatOfPoint>();
    hierarchy =new Mat();
    mHsv = new Mat();
    mHsvMask =new Mat();

    Imgproc.cvtColor(mRgba, mHsv, Imgproc.COLOR_RGB2HSV);

    Scalar lowerThreshold = new Scalar ( 0, 0, 0 ); // Blue color – lower hsv values
    Scalar upperThreshold = new Scalar ( 179, 255, 10 ); // Blue color – higher hsv values
    Core.inRange ( mHsv, lowerThreshold , upperThreshold, mHsvMask );

     //just some filter
   //Imgproc.dilate ( mHsvMask, mDilated, new Mat() );
    //Imgproc.erode(mDilated,mEroded,new Mat());


    Imgproc.findContours(mHsvMask, contours, hierarchy, Imgproc.RETR_TREE, Imgproc.CHAIN_APPROX_SIMPLE);

    for ( int contourIdx=0; contourIdx < contours.size(); contourIdx++ )
    {
        //Minimun size allowed for consideration
        MatOfPoint2f approxCurve = new MatOfPoint2f();
        MatOfPoint2f contour2f = new MatOfPoint2f(contours.get(contourIdx).toArray());

      //Processing on mMOP2f1 which is in type MatOfPoint2f
        double approxDistance = Imgproc.arcLength(contour2f,true)*0.02;
        Imgproc.approxPolyDP(contour2f,approxCurve,approxDistance,true);

        //convert to MatofPoint
        MatOfPoint point = new MatOfPoint(approxCurve.toArray());

        //get boundingrect from contour
        Rect rect = Imgproc.boundingRect(point);

        Imgproc.rectangle(mRgba,new Point(rect.x, rect.y), new Point(rect.x + rect.width, rect.y + rect.height), new Scalar(255, 0, 0, 255),3);
        //bisa Imgproc.rectangle(mRgba, rect.tl(), rect.br(), new Scalar(255, 0, 0),1, 8,0);


        //show contour kontur
        if(Imgproc.contourArea(contours.get(contourIdx))>100) {
            Imgproc.drawContours(mRgba, contours, contourIdx, new Scalar(0,255,0), 5);
        }
    }
    return mRgba;

希望有人在这方面有一些经验。谢谢..

4

1 回答 1

12

使用函数Imgproc.contourArea，您可以简单地找到所有轮廓的区域，而面积最大的轮廓将是最大的。

绘制最大轮廓的代码如下所示：

double maxVal = 0;
int maxValIdx = 0;
for (int contourIdx = 0; contourIdx < contours.size(); contourIdx++)
{
    double contourArea = Imgproc.contourArea(contours.get(contourIdx));
    if (maxVal < contourArea)
    {
        maxVal = contourArea;
        maxValIdx = contourIdx;
    }
}

Imgproc.drawContours(mRgba, contours, maxValIdx, new Scalar(0,255,0), 5);
于 2016-08-04T10:21:22.083 回答