0

我有一张存储付款的表格。我需要合并付款日期和付款日期。

所以我会有类似的东西：

DeudaId Date Value
1 2016-01-01 $100 <- This come from a table
1 2016-01-02 $0   <- This was calculated
1 2016-01-03 $0   <- This was calculated
1 2016-01-04 $100 <- This come from a table

我有这个必要的解决方案，但对我的情况来说太慢了：

CREATE OR REPLACE FUNCTION build_dates2()
 RETURNS TABLE (id INTEGER, cobrador_id INTEGER, fecha DATE)
 LANGUAGE plpgsql
 IMMUTABLE STRICT
AS $function$DECLARE min_date DATE;
DECLARE
    r RECORD;
    fecha RECORD;
BEGIN
    for r in (SELECT * FROM recaudo_deuda) LOOP
        for fecha in (select toFecha(r.fecha) + s.a AS dates from generate_series(0, r.plazo) as s(a)) LOOP
            return query VALUES ( r.id, r.cobrador_id, fecha.dates);
        END LOOP;
    END LOOP;
END
$function$;


SELECT * from  build_dates2()

我知道我可以创建另一个表并使用触发器存储数据。我想知道是否存在一种有效的方法来即时执行此操作。

我还尝试使用 recaudo_deuda 表的最小值/最大值生成日期列表，但是我看不到如何从中构建结果：

CREATE OR REPLACE FUNCTION public.build_dates()
 RETURNS TABLE(dates date)
 LANGUAGE plpgsql
 IMMUTABLE STRICT
AS $function$
DECLARE min_date DATE;
DECLARE dias INTEGER;
BEGIN
    SELECT min(fecha), extract(DAY from max(fecha) - min(fecha))
        from recaudo_deuda INTO min_date, dias;

  RETURN QUERY select min_date + s.a AS dates from generate_series(0,dias) as s(a);
END
$function$
4

2 回答 2

2

您可以使用一条 SQL 语句来执行此操作，如下所示：

select d.deudaid, s.a as date, coalesce(d.value, 0) as value
from (
   select min(fecha), max(fecha)
   from recaudo_deuda
) m (mi, mx)
  cross join lateral generate_series(m.mi, m.mx, interval '1' day) as s(a)
  left join recaudo_deuda d on d.fecha = s.a::date
order by s.a;
于 2016-08-03T21:07:03.847 回答
0

有点疯狂的解决方案。

简单的例子：

with t(x) as (values(1),(2),(5),(10),(11))
select
  x,
  generate_series(x, coalesce(lead(x) over (order by x) - 1, x)) as x_gaps,
  x = generate_series(x, coalesce(lead(x) over (order by x) - 1, x)) as x_real
from t;

转换为您的情况可能是（不确定我的列名是否准确）：

select
  deudaid,
  generate_series(fecha, coalesce(lead(fecha) over (order by fecha) - '1d', fecha), '1d') as fecha,
  (fecha = generate_series(fecha, coalesce(lead(fecha) over (order by fecha) - '1d', fecha), '1d'))::int * value as value
from
  recaudo_deuda;
于 2016-08-03T22:25:14.947 回答