java - 如何从 Android 中的另一个应用程序启动 Activity

Question

我想从我的 Android 应用程序中启动已安装的包。我认为使用意图是可能的，但我没有找到这样做的方法。有链接吗，在哪里可以找到资料？

score 754 · Accepted Answer

如果您不知道主要活动，则可以使用包名称来启动应用程序。

Intent launchIntent = getPackageManager().getLaunchIntentForPackage("com.package.address");
if (launchIntent != null) { 
    startActivity(launchIntent);//null pointer check in case package name was not found
}

score 256 · Accepted Answer

我知道这已经得到解答，但这是我实现类似内容的方式：

Intent intent = getPackageManager().getLaunchIntentForPackage("com.package.name");
if (intent != null) {
    // We found the activity now start the activity
    intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
    startActivity(intent);
} else {
    // Bring user to the market or let them choose an app?
    intent = new Intent(Intent.ACTION_VIEW);
    intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
    intent.setData(Uri.parse("market://details?id=" + "com.package.name"));
    startActivity(intent);
}

更好的是，方法如下：

public void startNewActivity(Context context, String packageName) {
    Intent intent = context.getPackageManager().getLaunchIntentForPackage(packageName);
    if (intent != null) {
        // We found the activity now start the activity
        intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
        context.startActivity(intent);
    } else {
        // Bring user to the market or let them choose an app?
        intent = new Intent(Intent.ACTION_VIEW);
        intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
        intent.setData(Uri.parse("market://details?id=" + packageName));
        context.startActivity(intent);
    }
}

删除重复代码：

public void startNewActivity(Context context, String packageName) {
    Intent intent = context.getPackageManager().getLaunchIntentForPackage(packageName);
    if (intent == null) {
        // Bring user to the market or let them choose an app?
        intent = new Intent(Intent.ACTION_VIEW);
        intent.setData(Uri.parse("market://details?id=" + packageName));
    }
    intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
    context.startActivity(intent);
}

score 166 · Accepted Answer

我找到了解决方案。在应用程序的清单文件中，我找到了包名称：com.package.address 和我要启动的主要活动的名称： MainActivity 以下代码启动此应用程序：

Intent intent = new Intent(Intent.ACTION_MAIN);
intent.setComponent(new ComponentName("com.package.address","com.package.address.MainActivity"));
startActivity(intent);

score 19 · Accepted Answer

// in onCreate method
String appName = "Gmail";
String packageName = "com.google.android.gm";
openApp(context, appName, packageName);

public static void openApp(Context context, String appName, String packageName) {
    if (isAppInstalled(context, packageName))
        if (isAppEnabled(context, packageName))
            context.startActivity(context.getPackageManager().getLaunchIntentForPackage(packageName));
        else Toast.makeText(context, appName + " app is not enabled.", Toast.LENGTH_SHORT).show();
    else Toast.makeText(context, appName + " app is not installed.", Toast.LENGTH_SHORT).show();
}

private static boolean isAppInstalled(Context context, String packageName) {
    PackageManager pm = context.getPackageManager();
    try {
        pm.getPackageInfo(packageName, PackageManager.GET_ACTIVITIES);
        return true;
    } catch (PackageManager.NameNotFoundException ignored) {
    }
    return false;
}

private static boolean isAppEnabled(Context context, String packageName) {
    boolean appStatus = false;
    try {
        ApplicationInfo ai = context.getPackageManager().getApplicationInfo(packageName, 0);
        if (ai != null) {
            appStatus = ai.enabled;
        }
    } catch (PackageManager.NameNotFoundException e) {
        e.printStackTrace();
    }
    return appStatus;
}

score 19 · Accepted Answer

根据评论编辑

在某些版本中 - 正如评论中所建议的那样 - 抛出的异常可能会有所不同。

因此下面的解决方案稍作修改

Intent launchIntent = null;
try{
   launchIntent = getPackageManager().getLaunchIntentForPackage("applicationId");
} catch (Exception ignored) {}

if(launchIntent == null){
    startActivity(new Intent(Intent.ACTION_VIEW).setData(Uri.parse("https://play.google.com/store/apps/details?id=" + "applicationId")));
} else {
    startActivity(launchIntent);
}

原始答案

虽然回答得很好，但如果未安装应用程序，有一个非常简单的实现可以处理。我这样做

try{
    startActivity(getPackageManager().getLaunchIntentForPackage("applicationId"));
} catch (PackageManager.NameNotFoundException e) {
    startActivity(new Intent(Intent.ACTION_VIEW).setData(Uri.parse("https://play.google.com/store/apps/details?id=" + "applicationId")));
}

将“applicationId”替换为您要打开的包，例如 com.google.maps 等。

score 17 · Accepted Answer

这是我从我的应用程序启动条形码/二维码扫描仪的示例，如果有人觉得它有用的话

Intent intent = new Intent("com.google.zxing.client.android.SCAN");
intent.setPackage("com.google.zxing.client.android");

try 
{
    startActivityForResult(intent, SCAN_REQUEST_CODE);
} 
catch (ActivityNotFoundException e) 
{
    //implement prompt dialog asking user to download the package
    AlertDialog.Builder downloadDialog = new AlertDialog.Builder(this);
    downloadDialog.setTitle(stringTitle);
    downloadDialog.setMessage(stringMessage);
    downloadDialog.setPositiveButton("yes",
            new DialogInterface.OnClickListener() 
            {
                public void onClick(DialogInterface dialogInterface, int i) 
                {
                    Uri uri = Uri.parse("market://search?q=pname:com.google.zxing.client.android");
                    Intent intent = new Intent(Intent.ACTION_VIEW, uri);
                    try
                    {
                        myActivity.this.startActivity(intent);
                    }
                    catch (ActivityNotFoundException e)
                    {
                        Dialogs.this.showAlert("ERROR", "Google Play Market not found!");
                    }
                }
            });
    downloadDialog.setNegativeButton("no",
            new DialogInterface.OnClickListener() 
            {
                public void onClick(DialogInterface dialog, int i) 
                {
                    dialog.dismiss();
                }
            });
    downloadDialog.show();
}

score 8 · Accepted Answer

// check for the app if it exist in the phone it will lunch it otherwise, it will search for the app in google play app in the phone and to avoid any crash, if no google play app installed in the phone, it will search for the app in the google play store using the browser : 

 public void onLunchAnotherApp() {

        final String appPackageName = getApplicationContext().getPackageName();

        Intent intent = getPackageManager().getLaunchIntentForPackage(appPackageName);
        if (intent != null) {

            intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
            startActivity(intent);

        } else {

            onGoToAnotherInAppStore(intent, appPackageName);

        }

    }

    public void onGoToAnotherInAppStore(Intent intent, String appPackageName) {

        try {

            intent = new Intent(Intent.ACTION_VIEW);
            intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
            intent.setData(Uri.parse("market://details?id=" + appPackageName));
            startActivity(intent);

        } catch (android.content.ActivityNotFoundException anfe) {

            intent = new Intent(Intent.ACTION_VIEW);
            intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
            intent.setData(Uri.parse("http://play.google.com/store/apps/details?id=" + appPackageName));
            startActivity(intent);

        }

    }

score 7 · Accepted Answer

如果您想打开另一个应用程序的特定活动，我们可以使用它。

Intent intent = new Intent(Intent.ACTION_MAIN, null);
intent.addCategory(Intent.CATEGORY_LAUNCHER);
final ComponentName cn = new ComponentName("com.android.settings", "com.android.settings.fuelgauge.PowerUsageSummary");
intent.setComponent(cn);
intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
try 
{
    startActivity(intent)
}catch(ActivityNotFoundException e){
    Toast.makeText(context,"Activity Not Found",Toast.LENGTH_SHORT).show()
}

如果您必须需要其他应用程序，您可以显示一个对话框，而不是显示 Toast。使用对话框，您可以将用户带到 Play-Store 以下载所需的应用程序。

score 5 · Accepted Answer

Intent.setClassName可以根据文档使用来启动应用程序的活动。

一个例子：

val activityName = "com.google.android.apps.muzei.MuzeiActivity" // target activity name
val packageName = "net.nurik.roman.muzei" // target package's name
val intent = Intent().setClassName(packageName, activityName)
startActivity(intent)

要在当前应用程序之外打开它，请在启动意图之前添加此标志。

intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)

这里有一个相关的答案

score 2 · Accepted Answer

如果您知道已安装的软件包所响应的数据和操作，您只需在启动意图实例之前将这些信息添加到您的意图实例中。

如果您有权访问其他应用程序的 AndroidManifest，则可以在那里查看所有需要的信息。

score 2 · Accepted Answer

private fun openOtherApp() {
        val sendIntent = packageManager.getLaunchIntentForPackage("org.mab.dhyanaqrscanner")
        startActivity(sendIntent)
        finishAffinity()
    }

score 2 · Accepted Answer

启动新活动的步骤如下：

1.获取包裹的意图

2.如果intent为null，将用户重定向到playstore

3.如果intent不是null open activity

public void launchNewActivity(Context context, String packageName) {
    Intent intent = null;
    if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.CUPCAKE) {
        intent = context.getPackageManager().getLaunchIntentForPackage(packageName);
    }
    if (intent == null) {
        try {
            intent = new Intent(Intent.ACTION_VIEW);
            intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
            intent.setData(Uri.parse("market://details?id=" + packageName));
            context.startActivity(intent);
        } catch (android.content.ActivityNotFoundException anfe) {
            startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + packageName)));
        }
    } else {
        intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
        context.startActivity(intent);
    }
}

score 1 · Accepted Answer

在科特林

fun openApplicationOrMarket(packageName: String) {
        var intent = requireContext().packageManager.getLaunchIntentForPackage(packageName)
        if (intent == null) {
            intent = Intent(Intent.ACTION_VIEW)
            intent.data = Uri.parse("market://details?id=$packageName")
        }

        intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
        requireContext().startActivity(intent)
    }

score 1 · Accepted Answer

如果未安装软件包，请传递软件包名称和要显示的消息；-)

void openApp(String appPackageName,String message){
    Intent launchIntent = getPackageManager().getLaunchIntentForPackage(appPackageName);
    if (launchIntent != null) {
        startActivity(launchIntent);
    } else {
        Toast.makeText(MainActivity.this, message, Toast.LENGTH_LONG).show();
        startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName)));
    }
}

score 1 · Accepted Answer

试试下面的代码：

Intent intent = new Intent(Intent.ACTION_MAIN);
intent.setComponent(new ComponentName("package_name", "Class_name"));
if (intent.resolveActivity(getPackageManager()) != null) 
{
   startActivity(intent);
}

score 1 · Accepted Answer

这将涵盖所有场景

1.获取包裹的意图

2.如果intent为null，将用户重定向到playstore

3.如果打开Playstore有问题，则在默认浏览器上打开。

var intent = activity!!.packageManager.getLaunchIntentForPackage("com.google.android.youtube")

          if (intent == null) {
            if (intent == null) {
                    intent = try {
                        Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=com.google.android.youtube"))
                    } catch (e: Exception) {
                        Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=com.google.android.youtube"))
                    }
                }
             startActivity(intent)

对于 Android 11（API 级别 30）或更高版本，在 AndroidManifest.xml 中，

<queries>
    <package android:name="com.google.android.youtube" />
    <package android:name="com.example.app" />
</queries>

或者只是我们可以允许所有包（不推荐）

<uses-permission android:name="android.permission.QUERY_ALL_PACKAGES" tools:ignore="QueryAllPackagesPermission" />

参考

Android 上的包可见性过滤

声明包可见性需求

score 1 · Accepted Answer

从 API 30 (Android 11) 开始，您可以使用 launchIntentForPackage 接收 nullpointerexception

val launchIntent: Intent? = activity.packageManager.getLaunchIntentForPackage("com.google.android.gm")
startActivity(launchIntent)

为避免这种情况，您需要将所需的包添加到清单中

<queries>
    <package android:name="com.google.android.gm" />
</queries>

这是文档 https://developer.android.com/training/package-visibility

以及中篇文章 https://medium.com/androiddevelopers/package-visibility-in-android-11-cc857f221cd9

score 0 · Accepted Answer

由于最近 kotlin 变得非常流行，我认为在 Kotlin 中也提供一个简单的解决方案是合适的。

var launchIntent: Intent? = null
try {
    launchIntent = packageManager.getLaunchIntentForPackage("applicationId")
} catch (ignored: Exception) {
}
if (launchIntent == null) {
    startActivity(Intent(Intent.ACTION_VIEW).setData(Uri.parse("https://play.google.com/store/apps/details?id=" + "applicationId")))
} else {
    startActivity(launchIntent)
}

score 0 · Accepted Answer

在 Kotlin 中，使用此代码从您当前的活动中启动另一个应用程序

       var intent = packageManager.getLaunchIntentForPackage("com.bankid.bus")


       //var intent = this.packageManager.getLaunchIntentForPackage("com.bankid.bus")
        if (intent != null) {
            // We found the activity now start the activity
            intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
            startActivity(intent)
        } else {
            // Bring user to the market or let them choose an app?
            intent = Intent(Intent.ACTION_VIEW)
            intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
            intent.data = Uri.parse("market://details?id=" + "com.bankid.bus")
            startActivity(intent)
        }

对于 android 版本 10+，您还需要在 AndroidManifest.xml 文件中添加标签，否则 getLaunchIntentForPackage() 将返回 null 即

<queries> <package android:name="com.bankid.bus" /> </queries>

java - 如何从 Android 中的另一个应用程序启动 Activity

19 回答 19

Related

Reference