1

我创建了一个包含大洲、国家和随机事实的属性列表,如下所示:

财产清单

我可以很容易地从属性列表中访问顶级键:

if let path = NSBundle.mainBundle().pathForResource("countryData", ofType: "plist") {
            dict = NSDictionary(contentsOfFile: path)
        }
countries += dict!.allKeys as! [String]

但是,如果我想访问 vanuatu 数组中的第二个元素,事情就会分崩离析。我认为 objectForKey 会获取国家/地区字典,然后再次使用 objectForKey 来获取国家/地区数组。但到目前为止,这还没有奏效。根本...

4

3 回答 3

3
if let path = NSBundle.mainBundle().pathForResource("countryData", ofType: "plist") {
            dict = NSDictionary(contentsOfFile: path)

            if let australia = dict["australia"] as? [String:AnyObject]{
                // access the second element's property here
            if let vanuatu = australia["vanuatu"] as? [String]{
                // Access the vanuatu here
                } 
            }
        }
于 2016-08-02T05:50:45.760 回答
2
if let path = NSBundle.mainBundle().pathForResource("Property List", ofType: "plist") {
       dict = NSDictionary(contentsOfFile: path)
        if let vanuatu = dict.objectForKey("australia") as? [String:AnyObject]{
            if let vanuatuArray = vanuatu["vanuatu"] as? [String]{
                print(vanuatuArray[1])
            }
        }

    }
于 2016-08-02T06:22:10.293 回答
1

您可以像这样从 plist 文件中获取数据。我为 countryCodes 创建了一个 plist 文件。

func fetchCounrtyCodes() -> [CountryCodes]{
let name = "name"
let dial_code = "dial_code"
let code = "code"

var countryArray = [CountryCodes]()

guard let filePath = NSBundle.mainBundle().pathForResource("CountryList", ofType: "json") else {
    print("File doesnot exist")
    return []
}
guard let jsonData = NSData(contentsOfFile: filePath) else  {
    print("error parsing data from file")
    return []
}
do {
    guard let jsonArray = try NSJSONSerialization.JSONObjectWithData(jsonData, options: NSJSONReadingOptions.AllowFragments) as? [[String:String]] else {
        print("json doesnot confirm to expected format")
        return []
    }
    countryArray = jsonArray.map({ (object) -> CountryCodes in
        return CountryCodes(name: object[name]!, dial_code:object[dial_code]!, code: object[code]!)
    })
}
catch {
    print("error\(error)")
}
return countryArray
}

struct CountryCodes{
var name = ""
var dial_code = ""
var code = ""
}
于 2016-08-02T07:19:15.710 回答