收到特定消息“退出”后shutdown()
如何调用?SocketServer
据我所知,调用serve_forever()
将阻塞服务器。
谢谢!
收到特定消息“退出”后shutdown()
如何调用?SocketServer
据我所知,调用serve_forever()
将阻塞服务器。
谢谢!
使用来源,卢克!
def serve_forever(self, poll_interval=0.5):
"""Handle one request at a time until shutdown.
Polls for shutdown every poll_interval seconds. Ignores
self.timeout. If you need to do periodic tasks, do them in
another thread.
"""
self.__is_shut_down.clear()
try:
while not self.__shutdown_request:
# XXX: Consider using another file descriptor or
# connecting to the socket to wake this up instead of
# polling. Polling reduces our responsiveness to a
# shutdown request and wastes cpu at all other times.
r, w, e = select.select([self], [], [], poll_interval)
if self in r:
self._handle_request_noblock()
finally:
self.__shutdown_request = False
self.__is_shut_down.set()
def shutdown(self):
"""Stops the serve_forever loop.
Blocks until the loop has finished. This must be called while
serve_forever() is running in another thread, or it will
deadlock.
"""
self.__shutdown_request = True
self.__is_shut_down.wait()
不,serve_forever
是定期检查标志(默认为 0.5 秒)。调用 shutdown 将引发此标志并导致 serve_forever 结束。