9

我有一个像这样的弹性搜索聚合查询。

{
    "aggs": {
        "customer": {
            "aggs": {
                "Total_Sale": {
                    "sum": {
                        "field": "amount"
                    }
                }
            },
            "terms": {
                "field": "org",
                "size": 50000
            }
        }
    }
}

它导致桶聚合如下

{
    "aggregations": {
        "customer": {
            "buckets": [
                {
                    "Total_Sale": { "value": 9999 },
                    "doc_count": 8,
                    "key": "cats"
                },
                {
                    "Total_Sale": { "value": 8888 },
                    "doc_count": 6,
                    "key": "tigers"
                },
                {
                    "Total_Sale": { "value": 444},
                    "doc_count": 5,
                    "key": "lions"
                },
                {
                    "Total_Sale": { "value": 555 },
                    "doc_count": 2,
                    "key": "wolves"
                }
           ]
       }
    }
}

我想要另一个基于 doc_count 的范围桶聚合。所以，需要的最终结果是 

{
    "buckets": [    
        {               
            "Sum_of_Total_Sale": 555, // If I can form bucket, I can get this using sum_bucket. So, getting bucket is important.
            "Sum_of_doc_count": 2, 
            "doc_count": 1, 
            "key": "*-3",   
            "to": 3.0       
        },              
        {               
            "Sum_of_Total_Sale": 9332,
            "Sum_of_doc_count": 11,
            "doc_count": 2, 
            "from": 4.0,    
            "key": "4-6",   
            "to": 6.0       
        },                  
        {               
            "Sum_of_Total_Sale": 9999,
            "Sum_of_doc_count": 8,
            "doc_count": 1, 
            "from": 7.0,    
            "key": "7-*"    
        }                   
    ]                   
}
  • Bucket Selector Aggregation 然后使用bucket sum 聚合将不起作用，因为范围有多个键。
  • 桶脚本聚合在桶内进行计算。
  • 我可以为每个文档添加脚本文档字段来帮助我创建这些存储桶吗？
4

1 回答 1

3

据我所知，没有任何聚合可以让您一次性完成此操作。但是，我不时使用一种技术来克服这个限制。这个想法是重复相同的terms/sum聚合，然后bucket_selector为您感兴趣的每个范围使用管道聚合。

POST index/_search
{
  "size": 0,
  "aggs": {
    "*-3": {
      "terms": {
        "field": "org",
        "size": 1000
      },
      "aggs": {
        "Total_Sale": {
          "sum": {
            "field": "amount"
          }
        },
        "*-3": {
          "bucket_selector": {
            "buckets_path": {
              "docCount": "_count"
            },
            "script": "params.docCount <= 3"
          }
        }
      }
    },
    "*-3_Total_Sales": {
      "sum_bucket": {
        "buckets_path": "*-3>Total_Sale"
      }
    },
    "*-3_Total_Docs": {
      "sum_bucket": {
        "buckets_path": "*-3>_count"
      }
    },
    "4-6": {
      "terms": {
        "field": "org",
        "size": 1000
      },
      "aggs": {
        "Total_Sale": {
          "sum": {
            "field": "amount"
          }
        },
        "4-6": {
          "bucket_selector": {
            "buckets_path": {
              "docCount": "_count"
            },
            "script": "params.docCount >= 4 && params.docCount <= 6"
          }
        }
      }
    },
    "4-6_Total_Sales": {
      "sum_bucket": {
        "buckets_path": "4-6>Total_Sale"
      }
    },
    "4-6_Total_Docs": {
      "sum_bucket": {
        "buckets_path": "4-6>_count"
      }
    },
    "7-*": {
      "terms": {
        "field": "org",
        "size": 1000
      },
      "aggs": {
        "Total_Sale": {
          "sum": {
            "field": "amount"
          }
        },
        "7-*": {
          "bucket_selector": {
            "buckets_path": {
              "docCount": "_count"
            },
            "script": "params.docCount >= 7"
          }
        }
      }
    },
    "7-*_Total_Sales": {
      "sum_bucket": {
        "buckets_path": "7-*>Total_Sale"
      }
    },
    "7_*_Total_Docs": {
      "sum_bucket": {
        "buckets_path": "7-*>_count"
      }
    }
  }
}

你会得到一个看起来像这样的答案，其中包含你在xyz_Total_Sales和xyz_Total_Docs结果中寻找的数字：

  "aggregations": {
    "*-3": {
      "doc_count_error_upper_bound": 0,
      "sum_other_doc_count": 0,
      "buckets": [
        {
          "key": "wolves",
          "doc_count": 2,
          "Total_Sale": {
            "value": 555
          }
        }
      ]
    },
    "7-*": {
      "doc_count_error_upper_bound": 0,
      "sum_other_doc_count": 0,
      "buckets": [
        {
          "key": "cats",
          "doc_count": 8,
          "Total_Sale": {
            "value": 9999
          }
        }
      ]
    },
    "4-6": {
      "doc_count_error_upper_bound": 0,
      "sum_other_doc_count": 0,
      "buckets": [
        {
          "key": "tigers",
          "doc_count": 6,
          "Total_Sale": {
            "value": 8888
          }
        },
        {
          "key": "lions",
          "doc_count": 5,
          "Total_Sale": {
            "value": 444
          }
        }
      ]
    },
    "*-3_Total_Sales": {
      "value": 555
    },
    "*-3_Total_Docs": {
      "value": 2
    },
    "4-6_Total_Sales": {
      "value": 9332
    },
    "4-6_Total_Docs": {
      "value": 11
    },
    "7-*_Total_Sales": {
      "value": 9999
    },
    "7_*_Total_Docs": {
      "value": 8
    }
  }
于 2018-09-29T04:21:49.147 回答