2

我在 Mac 上运行，并且有一个非常大的 .json 文件，其中包含超过 100k 个对象。

我想将文件分成许多文件（最好是 50-100）。

源文件

原始的 .json 文件是一个多维数组，看起来有点像这样：

[{
    "id": 1,
    "item_a": "this1",
    "item_b": "that1"
}, {
    "id": 2,
    "item_a": "this2",
    "item_b": "that2"
}, {
    "id": 3,
    "item_a": "this3",
    "item_b": "that3"
}, {
    "id": 4,
    "item_a": "this4",
    "item_b": "that4"
}, {
    "id": 5,
    "item_a": "this5",
    "item_b": "that5"
}]

期望的输出

如果将其拆分为三个文件，我希望输出如下所示：

文件 1：

[{
    "id": 1,
    "item_a": "this1",
    "item_b": "that1"
}, {
    "id": 2,
    "item_a": "this2",
    "item_b": "that2"
}]

文件 2：

[{
    "id": 3,
    "item_a": "this3",
    "item_b": "that3"
}, {
    "id": 4,
    "item_a": "this4",
    "item_b": "that4"
}]

文件 3：

[{
    "id": 5,
    "item_a": "this5",
    "item_b": "that5"
}]

任何想法将不胜感激。谢谢！

4

3 回答 3

3

@choroba 的回答非常有效和灵活。我有一个 bash 解决方案jq。

#!/bin/bash
i=0
file=0
for f in `cat data.json | jq -c -M '.[]'`; 
do 

   if [ $i -eq 2 ]; then

         ret=`jq --slurp "." /tmp/0.json /tmp/1.json  > File$file.json`;
         ret=`rm /tmp/0.json /tmp/1.json`; #cleanup

         ((file = file + 1));
     i=0
   fi
   ret=`echo $f > /tmp/$i.json`;
   ((i = i + 1));
done
if [ -f /tmp/0.json ]; then
    ret=`jq --slurp '.' /tmp/0.json > File$file.json`;
    ret=`rm /tmp/0.json`; #cleanup
fi
于 2016-07-26T08:48:37.543 回答
3

Perl 的救援：

#!/usr/bin/perl
use warnings;
use strict;

use JSON;

my $file_count = 5;  # You probably want 50 - 100 here.

my $json_text = do {
    local $/;
    open my $IN, '<', '1.json' or die $!;
    <$IN>
};
my $arr = decode_json($json_text);
my $size = @$arr / $file_count;
my $rest = @$arr % $file_count;

my $i = 1;
while (@$arr) {
    open my $OUT, '>', "file$i.json" or die $!;
    my @chunk = splice @$arr, 0, $size;
    ++$size if $i++ >= $file_count - $rest;
    print {$OUT} encode_json(\@chunk);
    close $OUT or die $!;
}
于 2016-07-26T08:00:04.180 回答
1 
$ cat tst.awk
/{/ && (++numOpens % 2) {
    if (++numOuts > 1) {
        print out, "}]"
        close(out)
    }
    out = "out" numOuts
    $0 = "[{"
}
{
    # print > out
    print out, $0
}

.

$ awk -f tst.awk file
out1 [{
out1     "id": 1,
out1     "item_a": "this1",
out1     "item_b": "that1"
out1 }, {
out1     "id": 2,
out1     "item_a": "this2",
out1     "item_b": "that2"
out1 }]
out2 [{
out2     "id": 3,
out2     "item_a": "this3",
out2     "item_b": "that3"
out2 }, {
out2     "id": 4,
out2     "item_a": "this4",
out2     "item_b": "that4"
out2 }]
out3 [{
out3     "id": 5,
out3     "item_a": "this5",
out3     "item_b": "that5"
out3 }]

在您测试并对此感到满意后，只需删除print out, $0并取消注释即可。# print > out

于 2016-07-26T14:28:47.447 回答