1

我可以在 elixir 上运行应用程序，但如果发生错误，一切都会存在。我只想在这种情况下重新启动我的应用程序。我正在使用主管，但甚至不知道它是否有效。以下是我的代码：-

mix.exs:-

def application do
[ 
  applications: [:httpotion, :zookeeper, :parallel, :poison],
  mod: {ServiceMonitor, []}
]
end

service_monitor.ex

defmodule ServiceMonitor do
  use Application

  def start(_type, _args) do
    import Supervisor.Spec, warn: false

    children = [
        worker(ServiceMonitor.Registry.setup, []),
    ]

    supervise(children, strategy: :one_for_one)
  end
end

注册表.ex

defmodule ServiceMonitor.Registry do

  def setup do
    zk = get_zk
    start(zk)
  end

  def start(zk) do
    #main code
  end
end

现在我正在使用以下命令运行我的应用程序：-

MIX_ENV=test mix run

这一切都运行良好，直到我在我的主代码中收到错误。应用程序存在并且永远不会重新启动。我收到的错误是：-

** (Mix) Could not start application service_monitor: exited in: ServiceMonitor.start(:normal, [])
** (EXIT) exited in: Task.await(%Task{owner: #PID<0.164.0>, pid: #PID<0.169.0>, ref: #Reference<0.0.2.1026>}, 3600000)
    ** (EXIT) an exception was raised:
        ** (MatchError) no match of right hand side value: {:error, :no_node}
            (service_monitor) lib/service_monitor/registry.ex:121: anonymous fn/3 in ServiceMonitor.Registry.remove_available_if_not_registered/3
            (elixir) lib/task/supervised.ex:89: Task.Supervised.do_apply/2
            (elixir) lib/task/supervised.ex:40: Task.Supervised.reply/5
            (stdlib) proc_lib.erl:240: :proc_lib.init_p_do_apply/3

请帮助我在哪里出错。我的要求是应用程序应在收到错误后立即自动重启。

4

1 回答 1

0

如果ServiceMonitor是你的 Supervisor 模块，它应该使用而不是根据thisSupervisor导入。Supervisor.spec

编辑：如果您仍想与您的主管一起去，请尝试Supervisor.start在代码末尾添加，就像示例中一样：

defmodule KVServer do
  use Application

  def start(_type, _args) do
    import Supervisor.Spec, warn: false

    children = [
    # worker(KVServer.Worker, [arg1, arg2, arg3])
    ]

   opts = [strategy: :one_for_one, name: KVServer.Supervisor]
   Supervisor.start_link(children, opts)
 end
end
于 2016-07-26T05:12:27.603 回答