android - ViewSwitcher 不会转到上一个视图

Question

您好，我正在尝试使用 a在 and和 anviewswitcher之间来回切换。我的视图从. 但不会切换回来。这是我的：TextViewEditTextedittexttextviewxml

<ViewSwitcher xmlns:android="http://schemas.android.com/apk/res/android"
            android:id="@+id/noteItemVS"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:layout_centerInParent="true">

            <TextView
                android:id="@+id/noteItemTextView"
                android:layout_width="match_parent"
                android:layout_height="wrap_content"
                android:clickable="true"
                android:text="textview"
                android:textAlignment="center" />

            <EditText
                android:id="@+id/noteItemEditText"
                android:layout_width="match_parent"
                android:layout_height="wrap_content"
                android:hint="edittext"
                android:textAlignment="center" />

        </ViewSwitcher>

我的切换代码是：

protected void switchViews(NoteItem note) {
        ViewSwitcher switcher = (ViewSwitcher)      context.findViewById(R.id.noteItemVS);
        View switchCheck = switcher.getCurrentView();
        if (switchCheck instanceof EditText) {
            EditText l = (EditText)switchCheck ;
            String x = l.getText().toString();
            Log.e("tree",x);
            if (!x.isEmpty()) {
                switcher.showPrevious();
                TextView myTV = (TextView) switcher.findViewById(R.id.noteItemTextView);
                myTV.setText(x);
            }
        }
        ; if (switchCheck instanceof TextView) {
            TextView l = (TextView) switchCheck;
            String x = l.getText().toString();
            switcher.showNext();
            EditText myEditText = (EditText) switcher.findViewById(R.id.noteItemEditText);
            myEditText.setText(x);
        }
    }

Answer 1

通过摆脱视图切换器，我能够解决问题。只需使用 View.Gone 和 View.Visibile

protected void switchViews(NoteItem note) {
        if (context.findViewById(R.id.noteItemTextView).getVisibility()==View.GONE) {
            EditText editText = (EditText) context.findViewById(R.id.noteItemEditText);
            String x  = editText.getText().toString();
            editText.setVisibility(View.GONE);
            TextView textView = (TextView) context.findViewById(R.id.noteItemTextView);
            textView.setVisibility(View.VISIBLE);
        } else {
            TextView textView = (TextView) context.findViewById(R.id.noteItemTextView);
            String x  = textView.getText().toString();
            textView.setVisibility(View.GONE);
            EditText editText = (EditText) context.findViewById(R.id.noteItemEditText);
            editText.setText(x);
            editText.setVisibility(View.VISIBLE);
        }
    }

Answer 2

发生这种情况是因为解释器同时处理了 if 语句，并且默认情况下后者覆盖了 forment 的值。试试下面的代码，它肯定会工作。

protected void switchViews() {
    ViewSwitcher switcher = (ViewSwitcher)findViewById(R.id.noteItemVS);
    View switchCheck = switcher.getCurrentView();
    if (switchCheck instanceof EditText) {
        EditText l = (EditText)switchCheck;
        String x = l.getText().toString();
        Log.e("tree",x);
        if (!x.isEmpty()) {
            switcher.showPrevious();
            TextView myTV = (TextView) switcher.findViewById(R.id.noteItemTextView);
            myTV.setText(x);
        }
    }else{
        TextView l = (TextView) switchCheck;
        String x = l.getText().toString();
        switcher.showNext();
        EditText myEditText = (EditText) switcher.findViewById(R.id.noteItemEditText);
        myEditText.setText(x);
    }
}