4

我正在尝试在我的应用程序中广播到不同的频道，但我无法让它工作。我也想写一个测试，但我不知道怎么做。

据我所知，我成功地从 notification_channel 广播了消息，但在 chat_channel 中没有收到。

通知应该发送到聊天。

notification_channel.ex

  def handle_in("new:group:recommendation", msg, socket) do
    payload = %{
        message: msg["message"],
        url: msg["url"],
        title: msg["title"],
        user_name: get_name_of_user(socket.assigns.user_grapqhl_id),
        user_grapqhl_id: socket.assigns.user_grapqhl_id
    }

    IO.puts "incomming"
    IO.inspect msg
    Enum.map(msg["groups"], fn(x) ->
        App.Endpoint.broadcast_from! self(), "chat:"<>x,
            "new:recommendation", payload
        end)
    {:reply, :ok, socket}

  end

聊天频道.ex

 def handle_in("new:recommendation", msg, socket) do
      IO.puts "i am a recommendation !"
      IO.inspect msg
      chat_msg = %{
         "creator_id" => msg["user_grapqhl_id"],
         "text" => msg["message"],
         "creator_name" => msg["user_name"]
      }

     broadcast! socket, "new:msg", create_chat_msg(chat_msg,socket)
     {:reply, :ok, socket}
  end

测试

  test "do we send a new:recommendation to chat ?", %{guardian_token: guardian_token} do
      nils_base_64 = Base.encode64("user:nils")

      {:ok, socket} = connect(UserSocket, %{})
      {:ok, _, socket1} = subscribe_and_join(socket, "notifications:"<>nils_base_64, %{"guardian_token" => guardian_token})
      {:ok, _, socket} = subscribe_and_join(socket1, "chat:Y2hhdDpjaGF0Mw==", %{"guardian_token" => guardian_token})

      payload = %{
          "message" => "look at this cool thing!",
          "url" => "link to stuff",
          "title" => "AWESOME EVENT",
          "groups" => ["Y2hhdDpjaGF0Mw==", "Y2hhdDpwdWJsaWM="]
      }

      reply = %{message: "look at this cool thing!", title: "AWESOME EVENT", url: "link to stuff", user_grapqhl_id: nils_base_64, user_name: "Nils Eriksson"}

      ref = push socket1, "new:group:recommendation", payload
      assert_reply ref, :ok
      assert_broadcast "new:recommendation", ^reply
  end

reply 该测试通过，我可以通过更改或注释掉广播来使其失败。我无法通过更改handle_in接收fail:please方式使其失败chat_channel。如果我在这种情况下发送更改 ref = push socket1, "new:group:recommendation", payload 以使其ref = push socket, "new:group:recommendation", payload不令人惊讶，那就是它会抱怨的事情。

这就是电线上的东西。

     Process mailbox:
   %Phoenix.Socket.Message{event: "init:msgs", payload: %{messages: []}, ref: nil, topic: "chat:Y2hhdDpjaGF0Mw=="}
   %Phoenix.Socket.Broadcast{event: "new:recommendation", payload: %{message: "look at this cool thing!", title: "AWESOME EVENTs", url: "link to stuff", user_grapqhl_id: "dXNlcjpuaWxz", user_name: "Nils Eriksson"}, topic: "chat:Y2hhdDpjaGF0Mw=="}
   %Phoenix.Socket.Message{event: "new:recommendation", payload: %{message: "look at this cool thing!", title: "AWESOME EVENTs", url: "link to stuff", user_grapqhl_id: "dXNlcjpuaWxz", user_name: "Nils Eriksson"}, ref: nil, topic: "chat:Y2hhdDpjaGF0Mw=="}

我使用通道身份验证，因为我使用的 elm 包还不支持套接字级别的身份验证。所以这就是它的样子chat

  def join("chat:" <> chat_id, %{"guardian_token" => token}, socket) do
  IO.puts chat_id
  case sign_in(socket, token) do
     {:ok, authed_socket, _guardian_params} ->
         Process.flag(:trap_exit, true)
         send(self, {:after_join})
         [_type, node_chat_id] = Node.from_global_id(chat_id)
         {:ok, assign(authed_socket, :chat_id, node_chat_id)}
     {:error, reason} ->
         IO.puts "Can't join channel cuz: " <> reason
       # handle error TODO
   end

结尾

4

2 回答 2

6

由于您使用.You 应该在您broadcast_from/4的.You 中使用：Endpointhandle_info/2chat_channel

alias Phoenix.Socket.Broadcast
  ...

def handle_info(%Broadcast{topic: _, event: ev, payload: payload}, socket) do
    IO.puts ev
    IO.inspect payload
    # do something with ev and payload( push or broadcast)
    {:noreply, socket}
  end

或者您可以从您的客户那里收听该事件：

chatChannel.on("new:recommendation", resp => {
   // doSomething with response
}

编辑：

让我们稍微解释一下channelandPubSub系统是如何工作的。

当您想要广播或推送带有有效负载的事件时。首先它会发送到PubSub系统，然后PubSub系统会将其发送到所有订阅者进程（channel），主题是在系统中channel注册的主题PubSub。

当您使用Endpoint.broadcast_from/4从服务器广播事件时。PubSub系统将接收带有有效负载的事件并将该事件广播到该频道注册的主题。

该通道将触发handle_out回调并将消息推送到客户端。所以在你的chat_channel你不需要handle_in“新：推荐”事件。你的客户只需要听那个事件。

chatChannel.on("new:recommendation", resp => {
   // do something with response
}

让我重写你的测试：

setup do
    nils_base_64 = Base.encode64("user:nils")
    {:ok, socket} = connect(UserSocket, %{})
    {:ok, _, socket} = subscribe_and_join(socket, "notifications:"<>nils_base_64, %{"guardian_token" => guardian_token})
    {:ok, socket: socket}
  end


test "do we send a new:recommendation to chat ?", %{socket: socket} do
      MyApp.Endpoint.subscribe("chat:Y2hhdDpjaGF0Mw==")

      payload = %{
          "message" => "look at this cool thing!",
          "url" => "link to stuff",
          "title" => "AWESOME EVENT",
          "groups" => ["Y2hhdDpjaGF0Mw==", "Y2hhdDpwdWJsaWM="]
      }



      reply = %Phoenix.Socket.Broadcast{message: "look at this cool thing!",
              title: "AWESOME EVENT",
              url: "link to stuff",
              user_grapqhl_id: nils_base_64,
              user_name: "Nils Eriksson"}

      ref = push socket, "new:group:recommendation", payload
      assert_reply ref, :ok
      assert_receive ^reply
  end

通过subscribe您要收听的主题，您可以确保您的频道收到消息assert_receive。这是测试broadcast不同频道的方法。

试一试告诉我。测试会通过的。

于 2016-07-24T13:29:14.087 回答
1

App.Endpoint.broadcast topic, event, payload与您的聊天频道的主题一起使用。它应该工作。

于 2017-04-14T03:32:46.007 回答