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Go-GL 的 Project 方法给了我意想不到的大屏幕坐标。

总结一下:

// Screen is 800x600.
projection := mgl32.Perspective(
    mgl32.DegToRad(45), // Field of view (45 degrees).
    800.0 / 600.0,      // Aspect ratio.
    0.1,                // Near Z at 0.1.
    10)                 // Far Z at 10.
camera := mgl32.LookAtV(
    mgl32.Vec3{0, 0.1, 10}, // Camera out on Z and slightly above.
    mgl32.Vec3{0, 0, 0},    // Looking at the origin.
    mgl32.Vec3{0, 1, 0}     // Up is positive Y.
model := mgl32.Ident4()     // Simple model matrix, to avoid confusion.
modelView := camera.Mul4(model) // The model-view matrix (== camera, here).

// Okay, so what does the origin translate to? Expect center-of-screen, with arbitrary-seeming depth.
origin := mgl32.Vec3{0, 0, 0}
screenOrigin := mgl32.Project(origin, modelView, projection, 0, 0, 800, 600)
fmt.Printf("Origin: (%v, %v, %v)", screenOrigin[0], screenOrigin[1], screenOrigin[2])

// What about the point 5 to the right of the origin?
// Expect increased X, but still less than screenWidth.
// Y and Z should be the same as for the origin.
// In my actual program, I drew (-1,-1,-1)-(1,1,1) cube at (5,0,0) and
// it is completely visible in the window.
test := mgl32.Vec3{5, 0, 0}
screenTest := mgl32.Project(test, modelView, projection, 0, 0, 800, 600)
fmt.Printf("Test:   (%v, %v, %v)", screenTest[0], screenTest[1], screenTest[2])

结果?

Origin: (400, 300, 5.500255)
Test:   (4021.32, 300, 5.500255)

4021.32?那是远离屏幕的方式!

我几乎消除了我能想到的所有变量,除了我用作基本提示的立方体渲染。我的代码基于此,但我移动了相机和立方体:https ://github.com/go-gl/examples/tree/master/gl41core-cube

如果我使用 (0, 0, 0) 作为输入向量并在 +X 中将 Ident4() 平移 5 个单位(这是有道理的),我会得到相同的结果。

那么我做错了什么?根据我正在绘制的立方体的位置,我预计 X = 625。

4

1 回答 1

3

出于好奇,我查看了 mgl32 的源代码。似乎该project方法是完全错误的:

obj4 := obj.Vec4(1)

vpp := projection.Mul4(modelview).Mul4x1(obj4)
win[0] = float32(initialX) + (float32(width)*(vpp[0]+1))/2
win[1] = float32(initialY) + (float32(height)*(vpp[1]+1))/2
win[2] = (vpp[2] + 1) / 2

正如人们可能注意到的那样,在矩阵乘法之后缺少透视除法,因此该函数在任何时候都不起作用w != 1.0f

在第一个示例中,由于 x 和 y 在矩阵相乘后为零,因此无法注意到错误,因此除以 w 不会产生差异(z 除外)。在第二个示例中,x 坐标不再为零,并且 bug 变得可见。

于 2016-07-20T07:27:11.277 回答