Pyflakes 在类方法的打印(到文件)命令中报告无效语法错误。这是代码:
class Controller():
def __init__(self):
self.base_url = ''
self.permissions = None
self.url = ''
self.description = ''
self.requests = ''
self.url_params = ''
self.data = ''
self.response = ''
self.pagination = ''
self.cmd_file = None
self.json_file = None
self.html_file = None
self.dict_file = None
self.app_name = ''
self.app = None
def json_doc(self):
if self.permissions:
permissions = self.permissions + '.'
else:
permissions = ''
print(
'{\n' \
'\t"URL": "' + self.url + '",\n' \
'\t"Description": "' + self.description + '.",\n' \
'\t"Requests": "' + self.requests + '",\n' \
'\t"Permissions": "' + permissions + '",\n' \
'\t"URL Parameters": "' + self.url_params + '",\n' \
'\t"Data": "' + self.data + '",\n' \
'\t"Response": "' + self.response + '",\n' \
'\t"Pagination": "' + self.pagination + '"\n' \
'}', \
file=self.json_file
)
这是错误:
curl_doc.py:79:17: invalid syntax
file=self.json_file
^
json_file 在我的代码中的其他地方设置。由于代码运行正常,这似乎是 pyflakes 的问题。使用的 pyflakes 命令是:
pyflakes curl_doc.py