r - 有谁知道如何在 R 中密件抄送？

Question

library("mailR")
    sender <- "sender@gmail.com"
    bcc<- c("BCC Recipient <bcc1@gmail.com.tr>","BCC Recipient<bcc2@gmail.com.tr>")
    send.mail(from = sender,
              bcc<- c("BCC Recipient <bcc1@gmail.com.tr>","BCC Recipient<bcc2@gmail.com.tr>"),
              subject = "subject",
              body = "BODY
              ",
              authenticate=TRUE,
                smtp = list(host.name = "smtp.gmail.com", port = 465, 
                          user.name = "YOURUSERNAME@gmail.com",            
                          passwd = "YOURPASSWORD", ssl = TRUE),
              send = TRUE,
              attach.files = c("C:/Users/admin/Desktop/Forecast.csv"),
              file.names = c("Demand_Forecast.csv"))

你知道如何用密件抄送发送邮件吗？格式是什么？它可以工作，但recipents可以看到对方

Answer 1

您错误地在函数中使用了赋值运算符send.mail()。

这应该有效：

library("mailR") sender <- "sender@gmail.com" bcc<- c("BCC Recipient <bcc1@gmail.com.tr>","BCC Recipient<bcc2@gmail.com.tr>") send.mail(from = sender, bcc = c("BCC Recipient <bcc1@gmail.com.tr>","BCC Recipient<bcc2@gmail.com.tr>"), subject = "subject", body = "BODY", authenticate=TRUE, smtp = list(host.name = "smtp.gmail.com", port = 465, user.name = "YOURUSERNAME@gmail.com",
passwd = "YOURPASSWORD", ssl = TRUE), send = TRUE, attach.files = c("C:/Users/admin/Desktop/Forecast.csv"), file.names = c("Demand_Forecast.csv"))