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我想从扩展运行测试ParentRunner。我这样做是为了学习，而不是任何特定的场景。我有下面的类，下面还有输出。有几件事我不明白： 1.为什么“describeChild”被重复调用3次？2. 为什么测试没有运行？（“doOne”和“doTwo”）？取消注释这一行： //Result result = JUnitCore.runClasses(arg0.getClass()); 正在执行测试，但我不明白为什么它会这样工作？3. 最重要的是 - 那行呢：@SuiteClasses({ChildOne.class, ChildTwo.class})？它对代码的行为没有影响......非常感谢任何回应的人:-)

套房类：

@RunWith(FamilyRunner.class)
@SuiteClasses({ChildOne.class, ChildTwo.class, ChildThree.class})
public class Suite {
//nothing here
}

跑者类：

public class FamilyRunner extends ParentRunner<ParentClass>{

public FamilyRunner(Class<?> klass) throws InitializationError {
        super(klass);
}


@Rule
public TestName name = new TestName();

@Override
protected List<ParentClass> getChildren() {

    List<ParentClass> list = new ArrayList<>();
    System.out.println("Adding items to list");
    list.add(new ChildOne());
    list.add(new ChildTwo());

    return list;
}


@Override
protected Description describeChild(ParentClass arg0) {
    System.out.println("describeChild class: " + arg0.getClass().getSimpleName());
    Description desc = Description.createTestDescription(name.getMethodName(), 
            name.getMethodName(), getClass().getAnnotations());

    return desc;
}

@Override
protected void runChild(ParentClass arg0, RunNotifier arg1) {
    System.out.println("runChild " + arg0.getClass().getSimpleName());
    //Result result = JUnitCore.runClasses(arg0.getClass());
}
}

和：

public class ParentClass {

    public ParentClass() {
         System.out.println("created parent class");
    }
}

public class ChildOne extends ParentClass {
    public ChildOne() {
        System.out.println("created ChildOne class");
    }

    @Test
    public void doOne(){
        System.out.println("doOne");
    }
}

public class ChildTwo extends ParentClass {
    public ChildTwo() {
        System.out.println("created ChildTwo class");
    }

    @Test
    public void doTwo(){
        System.out.println("doTwo");
    }
}

控制台打印：

Adding items to list
created parent class
created ChildOne class
created parent class
created ChildTwo class
describeChild class: ChildOne
describeChild class: ChildTwo
describeChild class: ChildOne
describeChild class: ChildTwo
describeChild class: ChildOne
describeChild class: ChildTwo
runChild ChildOne
runChild ChildTwo
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1 回答 1

0

我可以回答一些问题。

关于 @SuiteClasses({ChildOne.class, ChildTwo.class}) 您没有使用此注释值构建列表。

你可以这样做：

protected List<ParentClass> getChildren() {
    Annotation[] runnerAnnotations = super.getRunnerAnnotations();
    System.out.println(runnerAnnotations);

    Optional<Annotation> suitClass = Arrays.stream(runnerAnnotations)
            .filter(a -> a.annotationType().equals(SuiteClasses.class))
            .findFirst();

    List<ParentClass> list = new ArrayList<>();
    if (suitClass.isPresent()) {
        SuiteClasses s = (SuiteClasses) suitClass.get();
        s.value();
        System.out.println("Adding items to list");
        for (Class<?> c : s.value()) {
            Class<ParentClass> cp = (Class<ParentClass>) c;
            try {
                list.add(cp.newInstance());
            } catch (InstantiationException | IllegalAccessException e) {
                e.printStackTrace();
            }
        }
    }
    return list;
}

我认为您可以在 org.junit.runners.Suite 来源中找到更多信息：http: //grepcode.com/file/repo1.maven.org/maven2/junit/junit/4.8.1/org/junit/runners/Suite .java

于 2016-10-14T16:07:10.357 回答