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我有一个程序 (futval.py) 可以计算 10 年后的投资价值。我想修改程序，以便在 10 年后计算一次投资的价值，而不是计算一次投资的价值，而是在 10 年后计算每年投资的价值。我想在不使用累加器变量的情况下做到这一点。是否可以仅使用原始程序中存在的变量（投资，apr，i）来执行此操作？

# futval.py
# A program to compute the value of an investment
# carried 10 years into the future

def main():
    print "This program calculates the future value",
    print "of a 10-year investment."

    investment = input("Enter the initial investment: ")
    apr = input("Enter the annual interest rate: ")

    for i in range(10):
        investment = investment * (1 + apr)

    print "The value in 10 years is:", investment

main()

如果不引入“futval”累加器变量，我无法完成对程序的修改。

# futval10.py
# A program to compute the value of an annual investment
# carried 10 years into the future

def main():
    print "This program calculates the future value",
    print "of a 10-year annual investment."

    investment = input("Enter the annual investment: ")
    apr = input("Enter the annual interest rate: ")

    futval = 0

    for i in range(10):
        futval = (futval + investment) * (1+apr)

    print "The value in 10 years is:", futval

main()
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2 回答 2

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好的，如果您尝试做一些数学运算，您将自己看到解决方案。第一年我们有：

new_value = investment*(1 + apr)

对于第二个：

new_second_value = (new_value + investment)*(1+apr)

或者

new_second_value = (investment*(1 + apr) + investment)*(1+apr)

等等。如果你真的尝试将这些东西相乘，你会发现 10 年后最终的值是

investment*((1+apr)**10) + investment*((1+apr)**9)+...   etc

所以你的问题的解决方案就是

print("The value in 10 years is:", sum([investment*((1+apr)**i) for i in range(1, 11)]))

编辑：不知何故，我设法忽略了我写的只是一个几何级数的事实，所以答案更简单：

ten_years_annual_investment = investment*(apr+1)*((apr+1)**10 - 1)/apr
于 2016-07-08T21:45:46.170 回答
0

好吧，您不需要累加器，但您仍然需要一个临时变量来保存周期性投资的原始值：

def main():
    print "This program calculates the future value",
    print "of a 10-year investment."

    investment = input("Enter the initial investment: ")
    apr = input("Enter the annual interest rate: ")

    hold = investment
    investment = investment / apr

    for i in range(10):
        investment = investment * (1 + apr)

    investment = investment - hold / apr

    print "The value in 10 years is:", investment

main()
于 2016-07-08T23:18:04.187 回答