autoit - 如何在 AutoIT（SciTE 脚本编辑器）中获取当前选项卡的名称

Question

我想获取当前打开的选项卡的名称。

我试过这个：

$currentTabName1 = ControlCommand("Publish This! - Bulk Tools", "", "[CLASS:WindowsForms10.BUTTON.app.0.141b42a_r11_ad1;INSTANCE:16]", "CurrentTab", "")

但这只是让我拒绝。打开的选项卡。

提前致谢

Answer 1

您需要使用 GuiTab.au3 UDF。

这是我的做法。

#RequireAdmin
Opt("WinTitleMatchMode", 4) ;1=start, 2=subStr, 3=exact, 4=advanced, -1 to -4=Nocase

#include <GuiTab.au3>

$WindowTitle = "[CLASS:SciTEWindow]"
$Control = "[CLASS:SciTeTabCtrl; INSTANCE:1]"

$currentTabName1 = ControlCommand($WindowTitle, "", $Control, "CurrentTab", "")
$hWnd = ControlGetHandle($WindowTitle, "", $Control)

$array = _GUICtrlTab_GetItem ( $hWnd, $currentTabName1-1 ); -1 because we need 0 based

$CurrentTabText = StringTrimLeft($array[1], 1); trimming &

ConsoleWrite($CurrentTabText & @CRLF)

Answer 2

#include <GuiTab.au3>

; $control = yoru control instance name
$iIndex = _GUICtrlTab_GetCurSel($control)
$name = _GUICtrlTab_GetItemText($control, $iIndex)

_GUICtrlTab_GetCurSel

_GUICtrlTab_GetItemText