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我正在尝试使用教义的 DQL 加入自己的表。场景是:

我有一个产品属性值表,它通过参考表链接到产品表。产品属性值将用作产品的过滤器,因此,产品属性值表需要连接回自身以过滤多个属性。

我的方法如下:

public static function getProductsByCategoryCode($productCategoryCode, $currencyCode, Zend_Session_Namespace $filters = null)
{
    $products = Doctrine_Query::create()
        ->from('Products p')
        ->leftJoin('p.ProductCategories pc')
        ->leftJoin('p.ProductPrices pp')
        ->leftJoin('pp.Currencies c')
        ->where('pc.product_category_code = '. $productCategoryCode)
        ->addWhere('c.currency_code = "'. $currencyCode . '"');

    if($filters !== null)
    {   
        $i = 0;

        foreach($filters as $index => $value)
        {
            $alias = 'pav_' . (string)$i;

            $products
                ->leftJoin('p.ProductAttributeValues ' . $alias)
                ->addWhere($alias . '.product_attribute_code = "'. $index . '"')
                ->addWhere($alias . '.value = "'. $value . '"');

            $i++;
        }
    }

    die($products->getSql());

    return $products->execute();
}

问题是从getSql()调用中获得的结果 SQL 对产品属性值链接表有重复的别名(MySQL 错误:)#1066 - Not unique table/alias: 'p6'。据推测,这是由于产品和产品属性值之间的引用关系(产品属性值链接)被重用。

生成的 SQL 为:

SELECT 
p.product_code AS p__product_code, 
p.name AS p__name, 
p.description AS p__description, 
p2.product_category_code AS p2__product_category_code, 
p2.name AS p2__name, 
p2.category_route AS p2__category_route, 
p2.parent_product_category_code AS p2__parent_product_category_code, 
p2.lft AS p2__lft, 
p2.rgt AS p2__rgt, 
p2.level AS p2__level, 
p4.currency_code AS p4__currency_code, 
p4.product_code AS p4__product_code, 
p4.net_value AS p4__net_value, 
c.currency_code AS c__currency_code, 
p5.product_attribute_value_id AS p5__product_attribute_value_id, 
p5.product_attribute_code AS p5__product_attribute_code, 
p5.value AS p5__value, 
p7.product_attribute_value_id AS p7__product_attribute_value_id,
p7.product_attribute_code AS p7__product_attribute_code, 
p7.value AS p7__value 
FROM 
products p 
LEFT JOIN 
product_category_links p3 ON p.product_code = p3.product_code 
LEFT JOIN 
product_categories p2 ON p2.product_category_code = p3.product_category_code 
LEFT JOIN 
product_prices p4 ON p.product_code = p4.product_code 
LEFT JOIN 
currencies c ON p4.currency_code = c.currency_code 
LEFT JOIN 
product_attribute_value_links p6 ON p.product_code = p6.product_code 
LEFT JOIN 
product_attribute_values p5 ON 
p5.product_attribute_value_id = p6.product_attribute_value_id 
LEFT JOIN 
product_attribute_value_links p6 ON p.product_code = p6.product_code 
LEFT JOIN 
product_attribute_values p7 ON 
p7.product_attribute_value_id = p6.product_attribute_value_id 
WHERE 
p2.product_category_code = 10100 
AND 
c.currency_code = "GBP" 
AND 
p5.product_attribute_code = "BRAND" 
AND 
p5.value = "Advanced Hair Gear" 
AND 
p7.product_attribute_code = "SIZE" AND p7.value = "238 ml"

如您所见,P6 作为别名出现了两次。

有人知道使用 DQL 实现此目的的正确方法吗?

提前谢谢了。

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1 回答 1

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我不知道是否有更简单的解决方案,但您应该能够自己指定连接:

        ->leftJoin('p.ProductAttributeValuesLinks ' . $alias1)
        ->leftJoin($alias1 '.ProductAttributeValue ' . $alias2)

如果您在链接表上设置如下内容:

  relations:
    Product:
      class: Products
      foreignType: many
    ProductAttributeValue:
      class: ProductAttributeValues
      foreignType: many
于 2009-02-14T03:28:25.217 回答