4

我有一个虚拟自助餐厅项目,其中我有三个域类UserProductTransaction.

以下是类的定义方式:

class User {

    String name
    int employeeId
    long balance = 800
    static constraints = {
        balance(max: 800L)
    }   
}

class Product {

    String type 
    int quantityInStock
    float price
    static constraints = {
    }
}

class Transaction {

    int quantityBought
    static belongsTo = [user: User, product: Product]
    static constraints = {
    }
}

现在我想找出购买超过 2 个产品的用户数量/列表。我如何使用 Grails createCriteria 来做到这一点?

这是我尝试过的:

Transaction.createCriteria().list(){
    projections {
        groupProperty('user')
        'product' {
            count('id','numberOfPurchases')
        }
    }
    gt('numberOfPurchases',2)
}

但它给出了以下错误:

Stacktrace:

org.hibernate.QueryException: could not resolve property: numberOfPurchases of: cafeteria.dummy.Transaction 
at grails.orm.HibernateCriteriaBuilder.invokeMethod(HibernateCriteriaBuilder.java:1618)                    
at Script1.run(Script1.groovy:4)                                                                           
at org.grails.plugins.console.ConsoleService.eval(ConsoleService.groovy:37)                                
at org.grails.plugins.console.ConsoleController.execute(ConsoleController.groovy:59)                       
at grails.plugin.cache.web.filter.PageFragmentCachingFilter.doFilter(PageFragmentCachingFilter.java:195)   
at grails.plugin.cache.web.filter.AbstractFilter.doFilter(AbstractFilter.java:63)                          
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)                         
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)                         
at java.lang.Thread.run(Thread.java:745)                                                                   

如何numberOfPurchases在投影块之外访问此别名以便在其中使用它gt

4

1 回答 1

4

内部使用 Hibernate,目前 Hibernate在APIGORM中不支持。您无法获得投影块之外的原因是限制被添加到 where 子句并且您不能在子句中使用聚合别名。尽管 JPA 支持 have 子句。having clauseCriterianumberOfPurchaseswhere

但是,如果您仍然想使用 GORM Criteria 来实现这一点,您可以。但是您必须稍微修改一下您的查询,它不会涉及使用有子句,并且需要一个子查询。

修改后的查询将是:

SELECT DISTINCT this_.user_id FROM transaction this_ where 2 < (SELECT count(sub_.id) FROM transaction sub_ WHERE sub_.user_id=this_.user_id)

而 GORM 将是:

import org.hibernate.criterion.DetachedCriteria
import org.hibernate.criterion.Projections
import org.hibernate.criterion.Restrictions
import org.hibernate.criterion.Subqueries

DetachedCriteria subQuery = DetachedCriteria.forClass(Transaction, 'sub').with {
    setProjection Projections.count('sub.id')
    add Restrictions.eqProperty('sub.user', 'this.user')
}

List<User> users = Transaction.createCriteria().list() {
    projections {
        distinct("user")
    }
    add Subqueries.lt(2l, subQuery)
} 
于 2016-06-24T15:15:18.083 回答