我有一个投票应用程序的 graphql 环境,有用户、投票和投票。我在架构中的主要查询中,对我的应用程序中所有民意调查的查询(带有限制选项等等......),我也为每个用户提供了一个民意调查字段,我通常希望所有民意调查都是可排序的使用我自己的业务逻辑(例如大多数投票、最近投票等),我不希望为每个投票字段定义排序逻辑,并且通常使类型可排序。如何才能做到这一点?
这是我的代码,我目前只使用模拟数据库来测试和找出我需要的模式。现在到 GQL。
userType = new GraphQLObjectType({
name: 'User',
description: 'Registered user',
fields: (() => ({
id: {
type: new GraphQLNonNull(GraphQLID)
},
email: {
type: GraphQLString
},
password: {
type: GraphQLString
},
username: {
type: GraphQLString
},
polls: { // this should be sortable
type: new GraphQLList(pollType),
resolve: user => db.getUserPolls(user.id)
},
votes: {
type: new GraphQLList(voteType),
resolve: user => db.getUserVotes(user.id)
}
})),
resolve: id => db.getUsers()[id]
});
pollType = new GraphQLObjectType({
name: 'Poll',
description: 'Poll which can be voted by registered users',
fields: () => ({
id: {
type: new GraphQLNonNull(GraphQLID)
},
title: {
type: GraphQLString
},
options: {
type: new GraphQLList(GraphQLString),
},
votes: {
type: new GraphQLList(voteType),
resolve: poll => db.getPollVotes(poll.id)
},
author: {
type: userType,
resolve: poll => db.getPollAuthor(poll.id)
},
timestamp: {
type: GraphQLDate
}
})
});
voteType = new GraphQLObjectType({
name: 'Vote',
description: 'User vote on a poll',
fields: () => ({
id: {
type: new GraphQLNonNull(GraphQLID)
},
user: {
type: userType,
resolve: vote => db.getVoteUser(vote.id)
},
poll: {
type: pollType,
resolve: vote => db.getVotePoll(vote.id)
},
vote: {
type: GraphQLInt
},
timestamp: {
type: GraphQLDate
}
})
});
let schema = new GraphQLSchema({
query: new GraphQLObjectType({
name: 'Query',
fields: () => ({
user: {
type: userType,
args: {
id: {
type: new GraphQLNonNull(GraphQLID)
}
},
resolve: (root, {id}) => db.getUsers()[id]
},
polls: { //this should also be sorted
type: new GraphQLList(pollType),
resolve: () => db.getPolls()
},
votes: {
type: new GraphQLList(voteType),
resolve: () => db.getVotes()
}
})
})
});