所以我有两个集合,一个包含一系列邮政编码作为属性的城市,另一个包含邮政编码及其纬度和经度。
我想返回最接近坐标的城市。使用地理索引这很容易,但我遇到的问题是多次返回同一个城市,有时它可能是第一个和第三个最接近的,因为我正在搜索与另一个城市接壤的邮政编码。
城市示例数据:
[
{
"_key": "30936019",
"_id": "cities/30936019",
"_rev": "30936019",
"countryCode": "US",
"label": "Colorado Springs, CO",
"name": "Colorado Springs",
"postalCodes": [
"80904",
"80927"
],
"region": "CO"
},
{
"_key": "30983621",
"_id": "cities/30983621",
"_rev": "30983621",
"countryCode": "US",
"label": "Manitou Springs, CO",
"name": "Manitou Springs",
"postalCodes": [
"80829"
],
"region": "CO"
}
]
邮政编码示例数据:
[
{
"_key": "32132856",
"_id": "postalCodes/32132856",
"_rev": "32132856",
"countryCode": "US",
"location": [
38.9286,
-104.6583
],
"postalCode": "80927"
},
{
"_key": "32147422",
"_id": "postalCodes/32147422",
"_rev": "32147422",
"countryCode": "US",
"location": [
38.8533,
-104.8595
],
"postalCode": "80904"
},
{
"_key": "32172144",
"_id": "postalCodes/32172144",
"_rev": "32172144",
"countryCode": "US",
"location": [
38.855,
-104.9058
],
"postalCode": "80829"
}
]
以下查询有效,但作为 ArangoDB 新手,我想知道是否有更有效的方法来执行此操作:
FOR p IN WITHIN(postalCodes, 38.8609, -104.8734, 30000, 'distance')
FOR c IN cities
FILTER p.postalCode IN c.postalCodes AND c.countryCode == p.countryCode
COLLECT close = c._id AGGREGATE distance = MIN(p.distance)
FOR c2 IN cities
FILTER c2._id == close
SORT distance
RETURN c2