ios - iOS WebView - 在 SFSafariViewController 中打开链接

Question

所以我试图检测 webView 中的链接点击，然后在新的 URL 中显示这个 url，SFSafariViewController但是我遇到了一些问题。

有人有什么想法吗？

这就是我目前正在做的事情：

import UIKit
import SafariServices

class ViewController: UIViewController {

    @IBOutlet weak var webView: UIWebView!

    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.
        let localfilePath = NSBundle.mainBundle().URLForResource("index", withExtension: "html");
        let myRequest = NSURLRequest(URL: localfilePath!);
        webView.loadRequest(myRequest);

    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }


    func loadInView(webView: UIWebView, shouldStartLoadWithRequest request: NSURLRequest, navigationType: UIWebViewNavigationType) {

        if (navigationType == UIWebViewNavigationType.LinkClicked){
            let url = request.URL;

                let sfViewController = SFSafariViewController(URL:url!, entersReaderIfAvailable: true)

                self.presentViewController(sfViewController, animated: true, completion: { () -> Void in
                    print("May the force be with you!")
                })
        }

    }

}