我想根据 LastModifiedDate 或 CreatedDate 对记录进行排序,我希望两者中的最新应该出现在顶部。我试过了,order by CreatedDate DESC, LastModifiedDate DESC但这并没有显示最新的,它优先考虑 lastmodifieddate 然后是 CreatedDate
1360 次
3 回答
1
您可以在 2 列中比较 2 个日期并选择最新的
SELECT
CASE WHEN lastmodifiedDate > createdDate THEN lastmodifiedDate
ELSE createdDate
END AS LatestDate
FROM yourtable
对不起,我忘了你需要订购。然后你可以试试下面
select columns from yourtable order by CASE WHEN lastmodifiedDate > createdDate THEN lastmodifiedDate
ELSE createdDate
END AS LatestDate desc
于 2016-06-06T12:02:28.403 回答
1
您可以在 Order By 子句中使用 Case 语句,例如:
order by
case when CreatedDate > LastModifiedDate then CreatedDate else LastModifiedDate end DESC
于 2016-06-06T12:02:46.830 回答
0
DECLARE @A TABLE (ID INT,CREATION_DATE DATE,LAST_MODIFIED_DATE DATE)
INSERT INTO @A
VALUES
(1,'2016/06/06','2016/06/06'),
(2,'2016/06/06','2016/06/07'),
(3,'2016/06/06','2016/06/05')
SELECT S.* FROM
(
SELECT A.ID,A.CREATION_DATE,A.LAST_MODIFIED_DATE,
CASE
WHEN A.LAST_MODIFIED_DATE > A.CREATION_DATE THEN A.LAST_MODIFIED_DATE
ELSE A.CREATION_DATE
END AS ORDER_DATE
FROM @A A
) S
ORDER BY S.ORDER_DATE DESC
于 2016-06-06T12:17:07.720 回答