ios - void 函数中的非 void 返回值

Question

我怎么能把这个变量从这个函数中取出，以便我可以将坐标发送到另一个函数。当我尝试返回位置值时，我不明白为什么这会给我这个错误。

    placesClient!.currentPlaceWithCallback { (placeLikelihoods, error) -> Void in
        guard error == nil else {
            print("Current Place error: \(error!.localizedDescription)")
            return
        }
        var place : GMSPlace
        if let placeLikelihoods = placeLikelihoods {
            for likelihood in placeLikelihoods.likelihoods {
                place = likelihood.place
                print("Current Place name \(place.name) at likelihood \(likelihood.likelihood)")
                print("Current Place address \(place.formattedAddress)")
                print("Current Place attributions \(place.attributions)")
                print("Current PlaceID \(place.placeID)")
            }
        }
        return (place)
    }