我遵循了使用 Apache POI XSSF 构建工作簿的简单指南。按照相同的指南,我能够编写 Excel 工作表,但是当尝试从其中读取时,我收到代码后显示的错误。
代码:
try {
FileInputStream file = new FileInputStream(new File("howtodoinjava_demo.xlsx"));
// Create Workbook instance holding reference to .xlsx file
XSSFWorkbook workbook = new XSSFWorkbook(file);
// Get first/desired sheet from the workbook
XSSFSheet sheet = workbook.getSheetAt(0);
// Iterate through each rows one by one
Iterator<Row> rowIterator = sheet.iterator();
while (rowIterator.hasNext()) {
Row row = rowIterator.next();
// For each row, iterate through all the columns
Iterator<Cell> cellIterator = row.cellIterator();
while (cellIterator.hasNext()) {
Cell cell = cellIterator.next();
// Check the cell type and format accordingly
switch (cell.getCellType()) {
case Cell.CELL_TYPE_NUMERIC:
System.out.print(cell.getNumericCellValue() + "t");
break;
case Cell.CELL_TYPE_STRING:
System.out.print(cell.getStringCellValue() + "t");
break;
}
}
System.out.println("");
}
file.close();
} catch (Exception e) {
e.printStackTrace();
}
错误输出:
线程“主”java.lang.NoSuchFieldError 中的异常:org.apache.poi.openxml4j.opc.internal.ZipHelper.verifyZipHeader(ZipHelper.java:179) 处 org.apache.poi.openxml4j.opc.internal.ZipHelper 处的 RAW_XML_FILE_HEADER .openZipStream(ZipHelper.java:228) 在 org.apache.poi.openxml4j.opc.ZipPackage.(ZipPackage.java:93) 在 org.apache.poi.openxml4j.opc.OPCPackage.open(OPCPackage.java:294)在 org.apache.poi.util.PackageHelper.open(PackageHelper.java:37) 在 org.apache.poi.xssf.usermodel.XSSFWorkbook.(XSSFWorkbook.java:273) 在 com.wtolliver.spring.test.ReadExcel。 com.wtolliver.spring.test.App.main(App.java:17) 上的 readExcel(ReadExcel.java:18)