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对于查询：

SELECT
    cu.id id,
    cu.email email,
    SUM(case when(rt.type = 'credit' and ( re.type = 'account_refilling' OR re.type = 'site_publishing' OR re.type = 'tariff_buying' )) then rt.amount else 0 end ) transactions_sum
  FROM client_users cu
  LEFT JOIN referral_accounts ra ON ra.owner_id = cu.id
  LEFT JOIN referral_transactions rt ON rt.account_id = ra.id
  LEFT JOIN referral_events re ON re.id = rt.event_id
  GROUP BY cu.id, cu.email
  ORDER BY transactions_sum DESC

我收到错误：

Shards of relations in outer join queries must have 1-to-1 shard partitioning

这是什么意思，我应该怎么做才能解决它？

4

1 回答 1

1

您应该使用相同的方法分发您的表，并且它们应该具有相同的分片数

于 2016-06-03T12:01:08.393 回答